Write the sphere equation x^2 + y^2 + z^2 + 2x - 2y -2z = 33 in standard form, and hence find the center and the radius of this spere.

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
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Write the sphere equation x^2 + y^2 + z^2 + 2x - 2y -2z = 33 in standard form, and hence find the center and the radius of this spere.  I need a solution that is coherent and formatted. I cannot understand anything when you squish the explanation togther and I can't make heads or tails of what's going on. x2 does not mean x^2. Please format correctly.

Step 1
The given equation is:x2+y2+z2+2x-2y-
2z=33T0 write it in the standard form.To find the center and the radius of this sphere.
Step 2
X2+y2+z2+2x-2y-2z=33x2+2x+y2-2y+z2-2z=33x2+2x+1+y2-2y+1+z2-2z+1-3=33x+12+y-12+z-
12=33+3x+12+y-12+z-12=36This is in the standard form of sphere.Rewrite it in x--12+y-12+z-
12=620n comparing with x-a2+y-b2+z-
c2=r2, we get:a, b, c=-1, 1, 1 and r=6Therefore, the center is -1, 1, 1 and radius is 6
Transcribed Image Text:Step 1 The given equation is:x2+y2+z2+2x-2y- 2z=33T0 write it in the standard form.To find the center and the radius of this sphere. Step 2 X2+y2+z2+2x-2y-2z=33x2+2x+y2-2y+z2-2z=33x2+2x+1+y2-2y+1+z2-2z+1-3=33x+12+y-12+z- 12=33+3x+12+y-12+z-12=36This is in the standard form of sphere.Rewrite it in x--12+y-12+z- 12=620n comparing with x-a2+y-b2+z- c2=r2, we get:a, b, c=-1, 1, 1 and r=6Therefore, the center is -1, 1, 1 and radius is 6
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