C++ Write the procedure printSums which prints the sum of the first, last and middle element in thegiven array.Thearraywill have an odd size.arrays.cpp1#include using namespace std;345Demo.cpp1#include 2using namespace std;3#include "arrays.h"int main(){int al[] = {5,10,14,5,7};auto len1 = sizeof(a1) / sizeof(al[0]);print("al->", al, len1);printSums(al, len1);cout « endl;4789.101112int a2[] = {9,4,7};auto len2 = sizeof(a2) / sizeof(a2[0]);print("a2->", a2, len2);printSums(a2, len2);}1314151617CodeCheckReset

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Description: C++ Write the procedure printSums which prints the sum of the first, last and middle element in thegiven array.Thearraywill have an odd size.arrays.cpp1#include using namespace std;345Demo.cpp1#include 2using namespace std;3#include "arrays.h"int mai

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C++

Write the procedure printSums which prints the sum of the first, last and middle element in the
given array.
The
array
will have an odd size.
arrays.cpp
1
#include <iostream>
using namespace std;
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4
5
Demo.cpp
1
#include <iostream>
2
using namespace std;
3
#include "arrays.h"
int main()
{
int al[] = {5,10,14,5,7};
auto len1 = sizeof(a1) / sizeof(al[0]);
print("al->", al, len1);
printSums(al, len1);
cout « endl;
4
7
8
9.
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12
int a2[] = {9,4,7};
auto len2 = sizeof(a2) / sizeof(a2[0]);
print("a2->", a2, len2);
printSums(a2, len2);
}
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