Write the net ionic reactions and designate the nucleophile, substrate and the leaving group in the following reactions. CH3 CH3OCH2CH3 CH3CH2ONa + Nal a) 2CH3OH (CH3)3CCI b) (CH3)3 COCH3 CH3OH 2 + CI Br + 2NH3 c) NH2 + NH4Br

What is the product of the reaction of ethyl bromide with each of the following nucleophiles?   CH3CH2CH2O- CH3C≡C- (CH3)3N

The number of different monochlorinated constitutional isomers produced when each of the following undergo a uv light catalysed reaction with chlorine: Compound i: 2 Compound: ii: 1 Compound i: 3 Compound: ii: 4 Compound i: 4 Compound: ii: 2 Compound i: 5 Compound: ii: 1 Compound i: 6 Compound: ii: 3

Alcohols are acidic in nature. Therefore, a strong base can abstract the acidic hydrogen atom of the alcohol in a process known as deprotonation. The alcohol forms an alkoxide ion by losing the proton attached to the oxygen atom of the hydroxyl ( -OH) group. The alkoxide formed can act as a base or a nucleophile depending on the substrate and reaction conditions. However, not all bases can abstract the acidic proton of alcohols and not all alcohols easily lose the proton. Deprotonation depends on the strength of the base and the acidity of the alcohol. Strong bases, such as NaNH2, can easily abstract a proton from almost all alcohols. Likewise, more acidic alcohols lose a proton more easily. Determine which of the following reactions would undergo deprotonation based on the strength of the base and the acidity of the alcohol. Check all that apply. ► View Available Hint(s) CH3CH,OH + NH3 →CH,CH,O-NH CH3 CH3 H3C-C-H+NH3 → H3 C-C-H OH O-NH CH3CH2OH + NaNH, → CH3CH,O-Na* + NH3 CHC12 Cl₂…