Write the MIPS I code for the following C++ statements. y = ((x - 10) – (y + z)) – (x * 256); Use the following assumptions and requirements. Assume the registers that are not listed in the table are available, but not necessarily empty. • x, y, and z are C++ int-type variables. • Use the table for associations between the variables and their registers. Variables X Registers $s0 $s1 $s2 • Write each instruction based on the given comment. Write instructions below. The number leading each line is the line number. 1 # $t0 = x - 10 2 # $t1 = y + z 3 # $t2 = (x-10) - (y + z) %3D 4 # $t3 = x * 256 5 # y = ((x - 10) – (y + z)) – (x * 64)

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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Write the MIPS I code for the following C++ statements. y = ((x - 10) – (y + z)) – (x * 256);
Use the following assumptions and requirements.
Assume the registers that are not listed in the table are available, but not necessarily empty.
• X, y, and z are C++ int-type variables.
Use the table for associations between the variables and their registers.
Variables
Registers
$s0
$1
$2
Write each instruction based on the given comment.
Write instructions below. The number leading each line is the line number.
1
# $t0 = x - 10
2
# $t1 = y + z
3
# $t2 = (x-10) - (y + z)
4
# $t3 = x * 256
# y = ((x - 10) – (y + z)) – (x * 64)
Transcribed Image Text:Write the MIPS I code for the following C++ statements. y = ((x - 10) – (y + z)) – (x * 256); Use the following assumptions and requirements. Assume the registers that are not listed in the table are available, but not necessarily empty. • X, y, and z are C++ int-type variables. Use the table for associations between the variables and their registers. Variables Registers $s0 $1 $2 Write each instruction based on the given comment. Write instructions below. The number leading each line is the line number. 1 # $t0 = x - 10 2 # $t1 = y + z 3 # $t2 = (x-10) - (y + z) 4 # $t3 = x * 256 # y = ((x - 10) – (y + z)) – (x * 64)
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