write the magor producb formed by the fo llow wng reactron, Assume that you have enough of each reagont/ Reactant to drive the veactrion bo Completiion. Assume bhet there i's protic wek up aloe as nece ssarg ). NaBHey OH 2. Ht

Organic Chemistry: A Guided Inquiry
2nd Edition
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Andrei Straumanis
Chapter13: Substitution
Section: Chapter Questions
Problem 14CTQ
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**Problem Statement:**

Write the major product formed by the following reaction. Assume that you have enough of each reagent/reactant to drive the reaction to completion. Assume that there is a protic workup done as necessary.

**Reaction:**

\[ \text{(Reactant)} \]
  \[
  \begin{array}{c}
    \quad \quad \quad\quad 
    \begin{array}{ccccc}
    \quad O & \quad & \quad & O & \\
    // & OH & \quad & // & \quad & \\
    \left\backslash \right|  & & \left| \right/   & & \left\backslash \right| & & & \left| \right/   &&\\
    \end{array}
    \quad \quad \quad \quad 1.\text{NaBH}_4 \\
  \end{array}
  \ \quad 2.\text{H}^+
  \]

1. **Sodium Borohydride (NaBH₄)**
2. **Acidic Workup (H⁺)**

**Explanation:**

The provided reaction involves the reduction of a compound using Sodium Borohydride (NaBH₄) followed by an acidic workup (H⁺). Sodium Borohydride is a common reagent for the reduction of ketones, aldehydes, and esters. In this case, it will likely reduce the carbonyl group (C=O) to an alcohol (C-OH). The exact structure of the product will depend on the specific details of the reactants and conditions but assuming standard behavior of NaBH₄, the reaction generally converts carbonyl functionalities to their corresponding alcohols.
Transcribed Image Text:**Problem Statement:** Write the major product formed by the following reaction. Assume that you have enough of each reagent/reactant to drive the reaction to completion. Assume that there is a protic workup done as necessary. **Reaction:** \[ \text{(Reactant)} \] \[ \begin{array}{c} \quad \quad \quad\quad \begin{array}{ccccc} \quad O & \quad & \quad & O & \\ // & OH & \quad & // & \quad & \\ \left\backslash \right| & & \left| \right/ & & \left\backslash \right| & & & \left| \right/ &&\\ \end{array} \quad \quad \quad \quad 1.\text{NaBH}_4 \\ \end{array} \ \quad 2.\text{H}^+ \] 1. **Sodium Borohydride (NaBH₄)** 2. **Acidic Workup (H⁺)** **Explanation:** The provided reaction involves the reduction of a compound using Sodium Borohydride (NaBH₄) followed by an acidic workup (H⁺). Sodium Borohydride is a common reagent for the reduction of ketones, aldehydes, and esters. In this case, it will likely reduce the carbonyl group (C=O) to an alcohol (C-OH). The exact structure of the product will depend on the specific details of the reactants and conditions but assuming standard behavior of NaBH₄, the reaction generally converts carbonyl functionalities to their corresponding alcohols.
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