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Write the integral which gives the surface area generated when y = ¹ on 1 ≤ x ≤ 3 is revolved about the x axis. ○ 2π ₁³x²√1+16x6 dx ○ 2π ₁³√1 + 16x6 dx o fi x√1+16x6 dx 2π ₁³x²√1 +4x6dx O None of the other listed answers are correct. ○ 2π ₁³x²√1 +16x³ dx

Write the integral which gives the surface area generated when y = ¹ on 1 ≤ x ≤ 3 is revolved about the x axis. ○ 2π ₁³x²√1+16x6 dx ○ 2π ₁³√1 + 16x6 dx o fi x√1+16x6 dx 2π ₁³x²√1 +4x6dx O None of the other listed answers are correct. ○ 2π ₁³x²√1 +16x³ dx

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Write the integral which gives the surface area generated when y = x¹ on 1 ≤ x ≤ 3 is revolved about the x axis. O 2π ²³x². +16x6 dx ○ 2n ³√1+162% dr S²₁³ x 4 1+16x6 dx 2π f₁²³ O None of the other listed answers are correct. +4x6dx ○ 2π ²³ x² √1 + 16x³ dx
Transcribed Image Text:Write the integral which gives the surface area generated when y = x¹ on 1 ≤ x ≤ 3 is revolved about the x axis. O 2π ²³x². +16x6 dx ○ 2n ³√1+162% dr S²₁³ x 4 1+16x6 dx 2π f₁²³ O None of the other listed answers are correct. +4x6dx ○ 2π ²³ x² √1 + 16x³ dx
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