Write the given differential equation in the form L(y) = g(x), where L is a linear differential operator with constant coefficients. If possible, factor L. (Use D for the differential operator.) 4y" – 15y' – 4y = 5 = 5

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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**Title: Converting Differential Equations to Operator Form**

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**Objective:**  
Convert the differential equation into the form \( L(y) = g(x) \), where \( L \) is a linear differential operator with constant coefficients. Factor \( L \) if possible. Use \( D \) for the differential operator.

**Given Equation:**  
\[ 4y'' - 15y' - 4y = 5 \]

**Form Conversion:**  
\[ ( \underline{\quad\quad\quad} ) y = 5 \]

In this task, you need to express the differential equation by applying the differential operator \( D \), where \( D = \frac{d}{dx} \). This involves transforming the equation into an operator format and attempting to factor it if possible.

**Explanation:**

1. **Identify Components:**
   - \( y'' = D^2y \)
   - \( y' = Dy \)
   - \( y = y \)

2. **Operator Reformation:**
   - Substitute these into the equation to form the operator expression:  
   \[ 4D^2y - 15Dy - 4y = 5 \]

3. **Factoring:**
   - This operator \( L = 4D^2 - 15D - 4 \) may be factored into simpler differential operators if possible.


**Note:** This helps in simplifying and solving differential equations systematically using linear algebra techniques.
Transcribed Image Text:**Title: Converting Differential Equations to Operator Form** --- **Objective:** Convert the differential equation into the form \( L(y) = g(x) \), where \( L \) is a linear differential operator with constant coefficients. Factor \( L \) if possible. Use \( D \) for the differential operator. **Given Equation:** \[ 4y'' - 15y' - 4y = 5 \] **Form Conversion:** \[ ( \underline{\quad\quad\quad} ) y = 5 \] In this task, you need to express the differential equation by applying the differential operator \( D \), where \( D = \frac{d}{dx} \). This involves transforming the equation into an operator format and attempting to factor it if possible. **Explanation:** 1. **Identify Components:** - \( y'' = D^2y \) - \( y' = Dy \) - \( y = y \) 2. **Operator Reformation:** - Substitute these into the equation to form the operator expression: \[ 4D^2y - 15Dy - 4y = 5 \] 3. **Factoring:** - This operator \( L = 4D^2 - 15D - 4 \) may be factored into simpler differential operators if possible. **Note:** This helps in simplifying and solving differential equations systematically using linear algebra techniques.
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