Write the function in terms of unit step functions. Find the Laplace transform of the given function. F(s) = 3/s - 6 exp(-5s)/s 5/s²-5 exp(-s)/s² 3/s + 3 exp(-s)/s 5 + 10 exp(-3s) 3s + 6s² exp(5s) 5/s10 exp(-3s)/s 3 + 3 exp(-5s) 5/s3 exp(-10s)/s 0 No solution 5, f(t) = (³-²5 +23 0≤t<3

Q: 2- 1 2

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Q: -25 -35

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Q: # "S" Domain "t" Domain 1 4/5 (S+ 1)² /s 2 3 2/S + 4/s5- 1/(S +2) 1/ (S + 81) 5 (S+ 2) / (S² + 3)

A: The solution is given as

Q: F(s) F(s) = = s²-1 1-2s s²+4s+5

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Q: Q9. Use Laplace transform to solve the ODE. X-4x +3x =-8cos4t, x(0) =0, x(0) = 0 %3D

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Q: Determine the inverse Laplace transform of the function below. - 4s e s + 25

A: Fs=1s2+25 L-1Fs=sin5t L-1e-4ss2+25=L-1e-4Fs =ft-4ut-4             where u(t-4) is a step function…