Write the formula Consider the following null hypothesis: Ho: μ=30 Given a sample of n=16 and with x̅ =29, s=0.5 and α=0.05 - What is the alternative hypothesis H1 - What kind of test you are going to use? - t x̅ = - tα/2 = -What is your test conclusion? and why?
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Write the formula
Consider the following null hypothesis: Ho: μ=30
Given a sample of n=16 and with x̅ =29, s=0.5 and α=0.05
- What is the alternative hypothesis H1
- What kind of test you are going to use?
- t x̅ =
- tα/2 =
-What is your test conclusion? and why?
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- Consider testing the hypothesis H0: μ = 100 vs. Ha: μ ≠ 100. If the value of the test statistic is equal to 1.36, then what is the p-value?The hypothesis shown below is being tested. The test statistic calculated by the analyst was Z = +1.76 for a sample size of 200. Which one of the statements below the correct decision? H: µ=120 H,: µ 120 O Reject the null hypothesis at the 0.05 level of significance Do not reject the null hypothesis at the 0.05 level of significance Reject the null hypothesis because the p-value is .0392 which is significant O Do not reject the null hypothesis because the test statistic is less than 2.0A test of Ho: p = 0.5 versus Ha: p > 0.5 has a test statistic of z = 2.19. What is the P-value for the test? If the alternative hypothesis were Ha: p ≠≠0.5, what would be the value of the P-value?
- Decide whether you would reject or fail to reject the null hypothesis in the following situations: = 3.50, sD = 1.10, n = 12, a = .05, two-tailed test 95% CI = (0.20, 1.85) t = 2.98, t* = −2.36, one-tailed test to the left 90% CI = (−1.12, 4.36)You do a hypothesis test of H0: μ = 5 vs Ha: μ ≠ 5 at significance level 0.05. You collect a random sample and find your test statistic z = 2.10 What is the p value equal to? a. 0.5 b. 0.0358 c. cannot be determined d. 0.0179 e. 0.4821 f. 0.05Independent random samples from normal populations produced the results shown in the table to the right. Complete parts a through d below. a pyy What are the null and alternative hypotheses? OA. Ho: H₁-H₂ = 0.10 Ha: H₁-P₂20.10 B. Ho H₁-₂0 H₂H₁ ₂0 D. H₂:1₁-11₂=0 H₂H₁-H₂ <0 C. Ho: Hi-Hy=0.10 Ha: H₁-H₂ ≤0.10 What is the test statistic? (Round to two decimal places as needed.) Sample 1 2.2 1.2 3.3 1.1 2.9 Sample 2 2.9 3.3 2.9 3.4
- Only about 16% of all people can wiggle their ears. Is this percent different for millionaires? Of the 335 millionaires surveyed, 57 could wiggle their ears. What can be concluded at the αα = 0.05 level of significance? For this study, we should use Select an answer z-test for a population proportion t-test for a population mean The null and alternative hypotheses would be: H0:H0: ? p μ Select an answer > ≠ = < (please enter a decimal) H1:H1: ? p μ Select an answer ≠ < > = (Please enter a decimal) The test statistic ? t z = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 3 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer reject fail to reject accept the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton proportion is significantly different from 16% at αα = 0.05, so there is statistically significant evidence to conclude that the population…Aurora is conducting a one-sample ? test of the null hypothesis ?0:?=0.14H0:p=0.14 against the alternative ??:?<0.14Ha:p<0.14, where ?p is the population proportion. She requires her results to be statistically significant at a level of ?=0.01α=0.01. She selects a random sample of size ?n = 300 and calculates the sample proportion, ?̂ = 0.11. What is the value of the standardized test statistic and P-value of her test? Give z precise to two decimal places and the P-value precise to four decimal places.Aurora is conducting a one-sample ?z test of the null hypothesis ?0:?=0.12H0:p=0.12 against the alternative ??:?<0.12Ha:p<0.12, where ?p is the population proportion. She requires her results to be statistically significant at a level of ?=0.10α=0.10. She selects a random sample of size ?n = 200 and calculates the sample proportion, ?̂ p^ = 0.10. What is the value of the standardized test statistic and ?P-value of her test? Give ?z precise to two decimal places and the ?P-value precise to four decimal places.
- Only about 10% of all people can wiggle their ears. Is this percent different for millionaires? Of the 381 millionaires surveyed, 27 could wiggle their ears. What can be concluded at the αα = 0.10 level of significance? For this study, we should use Select an answer z-test for a population proportion t-test for a population mean The null and alternative hypotheses would be: H0:H0: ? p μ Select an answer ≠ > < = (please enter a decimal) H1:H1: ? p μ Select an answer = > ≠ < (Please enter a decimal) The test statistic ? t z = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 3 decimal places.) The p-value is ? ≤ > αα Based on this, we should Select an answer accept fail to reject reject the null hypothesis. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly different from 10% at αα = 0.10, so there is statistically insignificant evidence to conclude that the…Only about 13% of all people can wiggle their ears. Is this percent higher for millionaires? Of the 351 millionaires surveyed, 56 could wiggle their ears. What can be concluded at the αα = 0.10 level of significance? For this study, we should use Select an answer z-test for a population proportion t-test for a population mean The null and alternative hypotheses would be: H0:H0: ? p μ Select an answer > ≠ < = (please enter a decimal) H1:H1: ? p μ Select an answer < ≠ = > (Please enter a decimal) The test statistic ? t z = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 3 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer reject fail to reject accept the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton proportion is significantly higher than 13% at αα = 0.10, so there is statistically significant evidence to conclude that the population…Suppose there is a claim that a certain population has a mean, 4, that is different than 9. You want to test this claim. To do so, you collect a large random sample from the population and perform a hypothesis test at the 0.05 level of significance. To start this test, you write the null hypothesis, Ho, and the alternative hypothesis, H1, as follows. Hg: 4= 9 H: u=9 Suppose you also know the following information. The value of the test statistic based on the sample is -2.044 (rounded to 3 decimal places). The p-value is 0.041 (rounded to 3 decimal places). (a) Complete the steps below for this hypothesis test. Standard Normal Distribution 04 Step 1: Select one-tailed or two-tailed. O One-tailed Two-tailed 0.3+ Step 2: Enter the test statistic. (Round to 3 decimal places.) 0.2+ Step 3: Shade the area represented by the p-value. 0.1+ Step 4: Enter the p-value. (Round to 3 decimal places.) ? (b) Based on your answer to part (a), which statement below is true? O since the p-value is less…