Write the following as a function of x and y, eliminating the parameter t. Then graph the function and indicate the orientation of the curve æ = (t + 4)°, y =t – 1

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Problem Statement:**

Write the following as a function of \( x \) and \( y \), eliminating the parameter \( t \). Then graph the function and indicate the orientation of the curve.

\[
x = (t + 4)^2, \quad y = t - 1
\]

**Solution Steps:**

1. **Express \( t \) in terms of \( y \):**

   From the equation \( y = t - 1 \), solve for \( t \):
   \[
   t = y + 1
   \]

2. **Substitute \( t \) into the equation for \( x \):**

   Substitute \( t = y + 1 \) into the equation \( x = (t + 4)^2 \):
   \[
   x = ((y + 1) + 4)^2 = (y + 5)^2
   \]

3. **Final form of the function:**

   The equation of the curve in terms of \( x \) and \( y \) is:
   \[
   x = (y + 5)^2
   \]

4. **Graphing the Function:**

   - The equation \( x = (y + 5)^2 \) represents a parabola that opens to the right. 
   - The vertex of this parabola is at \( (0, -5) \).
   - The parabola will have a vertical line of symmetry along \( y = -5 \).

**Orientation of the Curve:**

- As \( t \) increases from negative infinity to positive infinity, \( y = t - 1 \) will also increase from negative infinity.
- Consequently, as \( y \) increases, \( x = (y + 5)^2 \) increases, indicating the curve moves to the right.
  
In summary, the solution has transformed the parametric equations into the Cartesian form, and the resulting parabola opens to the right with a vertex at \( (0, -5) \). The orientation indicates movement from left to right as \( t \) increases.
Transcribed Image Text:**Problem Statement:** Write the following as a function of \( x \) and \( y \), eliminating the parameter \( t \). Then graph the function and indicate the orientation of the curve. \[ x = (t + 4)^2, \quad y = t - 1 \] **Solution Steps:** 1. **Express \( t \) in terms of \( y \):** From the equation \( y = t - 1 \), solve for \( t \): \[ t = y + 1 \] 2. **Substitute \( t \) into the equation for \( x \):** Substitute \( t = y + 1 \) into the equation \( x = (t + 4)^2 \): \[ x = ((y + 1) + 4)^2 = (y + 5)^2 \] 3. **Final form of the function:** The equation of the curve in terms of \( x \) and \( y \) is: \[ x = (y + 5)^2 \] 4. **Graphing the Function:** - The equation \( x = (y + 5)^2 \) represents a parabola that opens to the right. - The vertex of this parabola is at \( (0, -5) \). - The parabola will have a vertical line of symmetry along \( y = -5 \). **Orientation of the Curve:** - As \( t \) increases from negative infinity to positive infinity, \( y = t - 1 \) will also increase from negative infinity. - Consequently, as \( y \) increases, \( x = (y + 5)^2 \) increases, indicating the curve moves to the right. In summary, the solution has transformed the parametric equations into the Cartesian form, and the resulting parabola opens to the right with a vertex at \( (0, -5) \). The orientation indicates movement from left to right as \( t \) increases.
Expert Solution
Step 1

Definition used - 

            Converting from parametric to cartesian form-

           There are two equations for x and y in terms of t, we solve for t from one equation and substitute it in other equation so t will eliminate and we get one equation in x and y. That is called the cartesian equation.

Step 2

  Given -           

                   x=(t+4)2, y=t-1

                  t=y+1

                Substituting the value of t in first equation, We got -

                  x=(y+1+4)2

                  x=y+52

 

 

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