Write the first five terms of the recursively defined sequence. 12 ak 2² a₁ = 4₁ ak + 1 Step 1 Note that the kth term of the sequence is defined by ak+1 Substitute k = 1 and Therefore, Step 2 Let a₁, a₂, a3, a4, and a5 be the first five terms of the sequence. Also note that a₁ = 4. = 1 ²₂=2²2²2²0 da₁ = 4 in ak + 1 Therefore, 1 2 Similarly, substitute k = 2 and = a2 N|T 2 = ²3 - 12/2² × ² = ²/1 аз = 12012². 4✔ = = 8 in ak + 1 4²: 1 = -1/201². ² = = 1 2 Zak². 2 = 8 ✔ 8
Write the first five terms of the recursively defined sequence. 12 ak 2² a₁ = 4₁ ak + 1 Step 1 Note that the kth term of the sequence is defined by ak+1 Substitute k = 1 and Therefore, Step 2 Let a₁, a₂, a3, a4, and a5 be the first five terms of the sequence. Also note that a₁ = 4. = 1 ²₂=2²2²2²0 da₁ = 4 in ak + 1 Therefore, 1 2 Similarly, substitute k = 2 and = a2 N|T 2 = ²3 - 12/2² × ² = ²/1 аз = 12012². 4✔ = = 8 in ak + 1 4²: 1 = -1/201². ² = = 1 2 Zak². 2 = 8 ✔ 8
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Related questions
Question
Transcribed Image Text:Write the first five terms of the recursively defined sequence.
12 ak 2²
a₁ = 4₁ ak + 1
Step 1
Note that the kth term of the sequence is defined by ak+1
Substitute k = 1 and
Therefore,
Step 2
Let a₁, a₂, a3, a4, and a5 be the first five terms of the sequence.
Also note that a₁ = 4.
=
1
²₂=2²2²2²0
da₁ = 4 in ak + 1
Therefore,
1
2
Similarly, substitute k = 2 and
=
a2
N|T
2
=
²3 - 12/2² × ² = ²/1
аз
=
12012².
4✔
=
= 8 in ak + 1
4²:
1==1/2² 12².
²
=
=
1
2
Zak².
2
= 8 ✔
8
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images
Recommended textbooks for you
Calculus: Early Transcendentals
Calculus
ISBN:
9781285741550
Author:
James Stewart
Publisher:
Cengage Learning
Thomas' Calculus (14th Edition)
Calculus
ISBN:
9780134438986
Author:
Joel R. Hass, Christopher E. Heil, Maurice D. Weir
Publisher:
PEARSON
Calculus: Early Transcendentals (3rd Edition)
Calculus
ISBN:
9780134763644
Author:
William L. Briggs, Lyle Cochran, Bernard Gillett, Eric Schulz
Publisher:
PEARSON
Calculus: Early Transcendentals
Calculus
ISBN:
9781285741550
Author:
James Stewart
Publisher:
Cengage Learning
Thomas' Calculus (14th Edition)
Calculus
ISBN:
9780134438986
Author:
Joel R. Hass, Christopher E. Heil, Maurice D. Weir
Publisher:
PEARSON
Calculus: Early Transcendentals (3rd Edition)
Calculus
ISBN:
9780134763644
Author:
William L. Briggs, Lyle Cochran, Bernard Gillett, Eric Schulz
Publisher:
PEARSON
Calculus: Early Transcendentals
Calculus
ISBN:
9781319050740
Author:
Jon Rogawski, Colin Adams, Robert Franzosa
Publisher:
W. H. Freeman
Calculus: Early Transcendental Functions
Calculus
ISBN:
9781337552516
Author:
Ron Larson, Bruce H. Edwards
Publisher:
Cengage Learning