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Write the equilibrium constant expression for this reaction: 2 CH3COO (aq)+C₂H6O₂(aq) → C6H₁004(aq) + 2OH(aq)

Write the equilibrium constant expression for this reaction: 2 CH3COO (aq)+C₂H6O₂(aq) → C6H₁004(aq) + 2OH(aq)

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Writing the Equilibrium Constant Expression for a Chemical Reaction** --- To write the equilibrium constant expression for the given chemical reaction, follow these steps. The reaction in question is: \[ \text{2 CH}_3\text{COO}^-_{(aq)} + \text{C}_2\text{H}_6\text{O}_2\text{(aq)} \rightarrow \text{C}_6\text{H}_{10}\text{O}_4\text{(aq)} + 2 \text{OH}^-_{(aq)} \] **Step-by-Step Process:** 1. **Identify the Products and Reactants:** - **Reactants:** \( \text{2 CH}_3 \text{COO}^- \) (aqueous) and \( \text{C}_2 \text{H}_6 \text{O}_2 \) (aqueous) - **Products:** \( \text{C}_6 \text{H}_{10} \text{O}_4 \) (aqueous) and \( 2 \text{OH}^- \) (aqueous) 2. **Write the General Form of the Equilibrium Constant Expression:** The equilibrium constant expression \( K_c \) for a general reaction of the form: \[ aA + bB \leftrightarrow cC + dD \] is given by: \[ K_c = \frac{[C]^c \cdot [D]^d}{[A]^a \cdot [B]^b} \] 3. **Apply the Reaction to the General Form:** - For the reactants: \( \text{2 CH}_3 \text{COO}^- \) and \( \text{C}_2 \text{H}_6 \text{O}_2 \), the concentrations will be raised to their respective coefficients. - For the products: \( \text{C}_6 \text{H}_{10} \text{O}_4 \) and \( 2 \text{OH}^- \), the concentrations will be raised to their respective coefficients. Plugging in the specific chemicals to the equilibrium constant formula gives: \[ K_c = \frac{[\text{C}_6 \text{H}_{10} \text{O}_4] \cdot [\text{
Transcribed Image Text:**Writing the Equilibrium Constant Expression for a Chemical Reaction** --- To write the equilibrium constant expression for the given chemical reaction, follow these steps. The reaction in question is: \[ \text{2 CH}_3\text{COO}^-_{(aq)} + \text{C}_2\text{H}_6\text{O}_2\text{(aq)} \rightarrow \text{C}_6\text{H}_{10}\text{O}_4\text{(aq)} + 2 \text{OH}^-_{(aq)} \] **Step-by-Step Process:** 1. **Identify the Products and Reactants:** - **Reactants:** \( \text{2 CH}_3 \text{COO}^- \) (aqueous) and \( \text{C}_2 \text{H}_6 \text{O}_2 \) (aqueous) - **Products:** \( \text{C}_6 \text{H}_{10} \text{O}_4 \) (aqueous) and \( 2 \text{OH}^- \) (aqueous) 2. **Write the General Form of the Equilibrium Constant Expression:** The equilibrium constant expression \( K_c \) for a general reaction of the form: \[ aA + bB \leftrightarrow cC + dD \] is given by: \[ K_c = \frac{[C]^c \cdot [D]^d}{[A]^a \cdot [B]^b} \] 3. **Apply the Reaction to the General Form:** - For the reactants: \( \text{2 CH}_3 \text{COO}^- \) and \( \text{C}_2 \text{H}_6 \text{O}_2 \), the concentrations will be raised to their respective coefficients. - For the products: \( \text{C}_6 \text{H}_{10} \text{O}_4 \) and \( 2 \text{OH}^- \), the concentrations will be raised to their respective coefficients. Plugging in the specific chemicals to the equilibrium constant formula gives: \[ K_c = \frac{[\text{C}_6 \text{H}_{10} \text{O}_4] \cdot [\text{
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