Write the equation of the line perpendicular to y-6-(* - 7) 3 and passing through the point (8,-1) Write in the format y = mx+b

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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**Problem Statement**

**Objective:**

Write the equation of the line perpendicular to \( y - 6 = -\frac{2}{3}(x - 7) \) and passing through the point (8, -1). Write in the format \( y = mx + b \).

### Instructions
1. Identify the slope of the given line.
2. Determine the slope of the perpendicular line.
3. Use the point-slope form of the line equation with the given point (8, -1) and the slope found in step 2.
4. Convert the equation to the format \( y = mx + b \).

**Help Section**

**Understanding the Problem:**

To find the equation of the line that is perpendicular to a given line, you must first understand that the slopes of two perpendicular lines are negative reciprocals of each other.

Given line: \( y - 6 = -\frac{2}{3}(x - 7) \)
- The slope of this line is \(-\frac{2}{3}\).

Slope of the perpendicular line:
- The perpendicular slope (m) is the negative reciprocal of \(-\frac{2}{3}\), which is \(\frac{3}{2}\).

Given point:
- The point through which the perpendicular line passes is (8, -1).

**Steps:**
1. Use the slope-intercept form: \( y = mx + b \).
2. Substitute the point (8, -1) into the equation to find b.

**Calculation:**
\[ -1 = \frac{3}{2}(8) + b \] 
\[ -1 = 12 + b \]
\[ b = -1 - 12 \]
\[ b = -13 \]

**Final Equation:**
\[ y = \frac{3}{2}x - 13 \]

### Answer Box
Using the calculations above, the perpendicular line's equation in the format \( y = mx + b \) is:

\[ y = \frac{3}{2}x - 13 \]
Transcribed Image Text:**Problem Statement** **Objective:** Write the equation of the line perpendicular to \( y - 6 = -\frac{2}{3}(x - 7) \) and passing through the point (8, -1). Write in the format \( y = mx + b \). ### Instructions 1. Identify the slope of the given line. 2. Determine the slope of the perpendicular line. 3. Use the point-slope form of the line equation with the given point (8, -1) and the slope found in step 2. 4. Convert the equation to the format \( y = mx + b \). **Help Section** **Understanding the Problem:** To find the equation of the line that is perpendicular to a given line, you must first understand that the slopes of two perpendicular lines are negative reciprocals of each other. Given line: \( y - 6 = -\frac{2}{3}(x - 7) \) - The slope of this line is \(-\frac{2}{3}\). Slope of the perpendicular line: - The perpendicular slope (m) is the negative reciprocal of \(-\frac{2}{3}\), which is \(\frac{3}{2}\). Given point: - The point through which the perpendicular line passes is (8, -1). **Steps:** 1. Use the slope-intercept form: \( y = mx + b \). 2. Substitute the point (8, -1) into the equation to find b. **Calculation:** \[ -1 = \frac{3}{2}(8) + b \] \[ -1 = 12 + b \] \[ b = -1 - 12 \] \[ b = -13 \] **Final Equation:** \[ y = \frac{3}{2}x - 13 \] ### Answer Box Using the calculations above, the perpendicular line's equation in the format \( y = mx + b \) is: \[ y = \frac{3}{2}x - 13 \]
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