Write the equation of the hyperbola with centre at (-3, –1), vertex at (-6, -1), one asymptote with equation 2x – 3y = -9. (x+ 3)² (y + 1)² = 1 4 (ӕ — 3)2 (y + 1)² 1 4 9 (x+ 3)² (y – 1)2 1 4 9. (x – 3)² (y + 1)² = 1 4 ||

Q: Find a function whose graph is the lower half of the hyperboloid -x2 - y2 + z2 = 1.

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Q: f.) x (y + 2) = 2(2x + 1) 2(2x + 1) y = mx + b form: Graph th

A: Given: To find:To write the above equation in  form.To draw the graph of the equation.

Q: Write the equation of the hyperbola 9x² - 36y2 - 18x144y - 459 = 0 in standard form (x - h)² (y -…

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Q: 4x2+y2-16y+8y+16=0 Identify the conic section by rewriting it in standard graphing form.

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Q: (b) Find an equation for the parabola that has axis x = -1 and passes [3] through the points (4,5)…

A: Directrix is a line which together with a point called the focus defines the set of points that form…

Q: Convert the following equation of a parabola into standard form. Select the correct answer below: O…

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Q: 3. Find the vertex for the parabola 4x + 2y² + 8 = 0. (a) (0, -2) (b) (-2,0) (c) (2, 2) (d) (-2,1)

A: The equation of the parabola is  4x+2y2+8=0

Q: 13. Which of the following is the equation of the graph shown? 2 Parabola Oy = - 3x? – 6x – 2 Oy = -…

A: The objective is to find the equation of the graph.

Q: The graph of a parabola is given.Match each graph to its equation

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Q: 1. A parabola has equation -12x + y? – 24 = 0. Write the equation in standard form.

A: The equation of the parabola is, - 12x + y² - 24 = 0 So, y² = 12x + 24

Q: The hyperbola with the given equation is centered at? * 16y² -9x² +36x + 96y - 36 = 0

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Q: What is the equation of the parabola that opens to the right and with vertex at (4,-2) and a latus…

A: Prabola

Q: Standardize the conic with the equation 7x2+4xy+4y2--2x-6y+1=0

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Q: The graph of a parabola is given.Match each graph to its equation

A: Some of the standard conic sections are parabola, hyperbola, ellipse, circle. among others. The…

Q: 7. Find the equation of the parabola in standard form vertex at the origin passing through the point…

A: The equation of the parabola in vertex form with vertex (h.k) is y = a(x-h)2+k Here the vertex is at…

Q: The vertex of the parabola given by the equation x2 = 20 y is O (0,0) O (4,5) O (0,5) O (4,0)

A: Vertex of the parabola

Q: If a parabola y=ax2+ky=ax2+k has vertex (0,−1)(0,−1) and passes through the point (4,2)(4,2). What…

A: A Parabola y=ax2+k       ...(1) has Vertex (0,-1) and Passes through the Point (4,2)

Q: y = 3(x+4/3)^2 - 2 How can I determine the x and y intercepts for this parabola?

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Q: Find the directrix of the parabola described by the equation 6 (x – 3) + (y + 2)? = 0 O x = } O x =…

A: The  parabola with vertex at (h,k) and focus at (h-a,k) has a standard equation, (y-k)2=-4a(x-h) The…

Q: Find the y-intercept and any x-intercept(s) of the parabola with equation y = -(x + 7) + 16. If the…

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Q: Arrange the parabolas represented by the equations according to the positions of their foci on the…

A: The standard form of a parabola is  (x – h)2 = a(y – k) where (h, k) is the vertex.

Q: The vertices of the ellipse given by = 1 are (2, 1) and (1, 2) (0, 1) and (0, – 1) - O A. В. (-2, 0)…

A: Given:- x2/4+y2/1 = 1 To find:- Vertices of given equation of ellipse

Q: Graph the hyperbola (y+3)2/16-(x+6)2/4=1

A: The given equation is (y+3)2/16-(x+6)2/4=1.

Q: Convert the following equation of a parabola into standard form. Select the correct answer below: O…

A: We are required to: Change the equation of parabola -2x+y2-2y-1=0 into standard form.