Write the equation of a line that is perpendicular to y = 0.25x -7 and that passes through the point (-6, 8).

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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**Problem Statement:**

Write the equation of a line that is *perpendicular* to \( y = 0.25x - 7 \) and that passes through the point \((-6, 8)\).

**Explanation:**

To solve this problem:

1. **Identify the Slope of the Given Line:**
   The given line is \( y = 0.25x - 7 \), which is in slope-intercept form \( y = mx + b \). Here, the slope \( m = 0.25 \).

2. **Determine the Slope of the Perpendicular Line:**
   The slope of a line perpendicular to another is the negative reciprocal of the original line’s slope. Therefore, the perpendicular slope is \( m = -\frac{1}{0.25} = -4 \).

3. **Use the Point-Slope Form to Find the Equation:**
   The point-slope form of a line's equation is \( y - y_1 = m(x - x_1) \), where \( m \) is the slope and \((x_1, y_1)\) is the point the line passes through.
   
   Substituting the slope \(-4\) and the point \((-6, 8)\) into the formula:
   \[
   y - 8 = -4(x + 6)
   \]

4. **Simplify to Find the Equation:**
   Distribute and simplify:
   \[
   y - 8 = -4x - 24
   \]
   \[
   y = -4x - 16
   \]

The equation of the line perpendicular to \( y = 0.25x - 7 \) and passing through \((-6, 8)\) is \( y = -4x - 16 \).
Transcribed Image Text:**Problem Statement:** Write the equation of a line that is *perpendicular* to \( y = 0.25x - 7 \) and that passes through the point \((-6, 8)\). **Explanation:** To solve this problem: 1. **Identify the Slope of the Given Line:** The given line is \( y = 0.25x - 7 \), which is in slope-intercept form \( y = mx + b \). Here, the slope \( m = 0.25 \). 2. **Determine the Slope of the Perpendicular Line:** The slope of a line perpendicular to another is the negative reciprocal of the original line’s slope. Therefore, the perpendicular slope is \( m = -\frac{1}{0.25} = -4 \). 3. **Use the Point-Slope Form to Find the Equation:** The point-slope form of a line's equation is \( y - y_1 = m(x - x_1) \), where \( m \) is the slope and \((x_1, y_1)\) is the point the line passes through. Substituting the slope \(-4\) and the point \((-6, 8)\) into the formula: \[ y - 8 = -4(x + 6) \] 4. **Simplify to Find the Equation:** Distribute and simplify: \[ y - 8 = -4x - 24 \] \[ y = -4x - 16 \] The equation of the line perpendicular to \( y = 0.25x - 7 \) and passing through \((-6, 8)\) is \( y = -4x - 16 \).
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