Part 2
Ionic compounds are made up of anion and cations
And hence any ionic compound will have at least 1 anion and 1 cation
Since we have been given with 2 cations and 2 anions
Hence each combination of anion and cation will give 1 ionic compound
hence total 4 binary ionic compound are possible
1) Cation Fe2+ anion CN-
Since the ionic compound will have no net charge
hence the charge of cations should be equal to charge of anions
And since here we have 2+ on cation and 1- on anion
hence 1 cation and 2 anion will form the compound ( because to balance 2+ on cation we need 2 anions with 1-)
Hence the ionic compound is Fe(CN)2
2) Cation Fe2+ anion NO3-
Since the ionic compound will have no net charge
hence the charge of cations should be equal to charge of anions
And since here we have 2+ on cation and 1- on anion
hence 1 cation and 2 anion will form the compound ( because to balance 2+ on cation we need 2 anions with 1-)
Hence the ionic compound is Fe(NO3)2
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Solved in 5 steps
