Homework Help is Here – Start Your Trial Now!
Science
Chemistry
Write the balanced equation for the following situation. List the reaction type. Tell the amounts of every substance that remains in the container at the end of the reaction. Assume that all reactions go to completion If only stoichiometry, tell how much of the excess reactant is used!!!! Reaction Type: a. Combination Reaction b. Decomposition Reaction c. Single Displacement / THIS IS ONE TYPE OF Oxidation Reduction Reaction d. Precipitation Reaction e. Gaseous Reaction f. Neutralization Reaction g. Combustion Reaction Follow the format used in the image. 1.95 g iron(III) chloride and 25.00 mL of a 0.250 M sodium hydroxide solution 2. N₂ (g) + 3 H₂ (g) - 2 NH3(g) (This is LIMITING REACTANT: N₂ is the Limiting Reactant) Grams of Product (List the Product and the Amount): 0.75168 g NH3 Reaction Type: Combination or Single Displacement (which is also called Oxidation-Reduction) ? g NH3 61.802 cg N₂ x 1g N₂ LR x 1 mol N₂ x 28.02 g N₂ 1 x 10² cg N₂ ? g NH3 = 61.802 cg H₂ x 1g H₂ 1 x 10² g H₂ 1 x 10² cg N₂ X Amount of H₂ Remaining in the Container 1 mol H₂ x 2.02 g H₂ 2 mol NH₂ x 17.04 g NH3 0.75168 g NH3 ******* THEORETICAL YIELD 1 mol N₂ 1 mol NH How much N₂ remains in the vessel? You will use the LIMITING REACTANT and determine how much H₂ was USED in the RXN. ? g H₂ USED= 61.802 cg N2 x 1g N₂ x 1 mol N₂ x 3 mol H₂ 28.02 g N₂ 1 mol N₂ H₂ amount given - H₂ amount USED 2 mol NH x 17.04 g NH3 = 3.3756 g NH3 3 mol H₂ 1 mol Nha x 2.02 g H₂= 0.13366 g H₂ 1 mol H₂ 0.61802 g H₂ GIVEN 0.13366 g H₂ USED -0.48436 g of H₂--LEFT OVER-EXCESS

Write the balanced equation for the following situation. List the reaction type. Tell the amounts of every substance that remains in the container at the end of the reaction. Assume that all reactions go to completion If only stoichiometry, tell how much of the excess reactant is used!!!! Reaction Type: a. Combination Reaction b. Decomposition Reaction c. Single Displacement / THIS IS ONE TYPE OF Oxidation Reduction Reaction d. Precipitation Reaction e. Gaseous Reaction f. Neutralization Reaction g. Combustion Reaction Follow the format used in the image. 1.95 g iron(III) chloride and 25.00 mL of a 0.250 M sodium hydroxide solution 2. N₂ (g) + 3 H₂ (g) - 2 NH3(g) (This is LIMITING REACTANT: N₂ is the Limiting Reactant) Grams of Product (List the Product and the Amount): 0.75168 g NH3 Reaction Type: Combination or Single Displacement (which is also called Oxidation-Reduction) ? g NH3 61.802 cg N₂ x 1g N₂ LR x 1 mol N₂ x 28.02 g N₂ 1 x 10² cg N₂ ? g NH3 = 61.802 cg H₂ x 1g H₂ 1 x 10² g H₂ 1 x 10² cg N₂ X Amount of H₂ Remaining in the Container 1 mol H₂ x 2.02 g H₂ 2 mol NH₂ x 17.04 g NH3 0.75168 g NH3 ******* THEORETICAL YIELD 1 mol N₂ 1 mol NH How much N₂ remains in the vessel? You will use the LIMITING REACTANT and determine how much H₂ was USED in the RXN. ? g H₂ USED= 61.802 cg N2 x 1g N₂ x 1 mol N₂ x 3 mol H₂ 28.02 g N₂ 1 mol N₂ H₂ amount given - H₂ amount USED 2 mol NH x 17.04 g NH3 = 3.3756 g NH3 3 mol H₂ 1 mol Nha x 2.02 g H₂= 0.13366 g H₂ 1 mol H₂ 0.61802 g H₂ GIVEN 0.13366 g H₂ USED -0.48436 g of H₂--LEFT OVER-EXCESS

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
See similar textbooks
icon
Related questions
Question
100%
Write the balanced equation for the following situation. List the reaction type. Tell the amounts of every substance that remains in the container at the end of the reaction. Assume that all reactions go to completion. If only stoichiometry, tell how much of the excess reactant is used!!!! Reaction Type: a. Combination Reaction b. Decomposition Reaction c. Single Displacement / THIS IS ONE TYPE OF Oxidation Reduction Reaction d. Precipitation Reaction e. Gaseous Reaction f. Neutralization Reaction g. Combustion Reaction Follow the format used in the image. 1.95 g iron(III) chloride and 25.00 mL of a 0.250 M sodium hydroxide solution 2. N₂(g) + 3 H₂(g) → 2 NH3 (g) (This is LIMITING REACTANT: N₂ is the Limiting Reactant) Grams of Product (List the Product and the Amount): 0.75168 g NH3 Reaction Type: Combination or Single Displacement (which is also called Oxidation-Reduction) ? g NH3 = 61.802 cg N₂ x 1g N₂ LR 1 x 10² cg N₂ ? g NH3 = 61.802 cg H₂ x 1g H₂ 1 x 10² g H₂ x x 1 mol N₂ x 28.02 g N₂ 1 mol H₂ x 2.02 g H₂ 2 mol NH3 x 17.04 g NH3 = 0.75168 g NH3 ******* THEORETICAL YIELD 1 mol N₂ 1 mol NH3 2 mol NH3 x 17.04 g NH3 = 3.3756 g NH3 3 mol H₂ 1 mol NH3 How much N₂ remains in the vessel? You will use the LIMITING REACTANT and determine how much H₂ was USED in the RXN. ? g H₂ USED = 61.802 cg N₂ x 1g N₂ x 1 mol N₂ x 3 mol H₂ 1 x 10² cg N₂ 28.02 g N₂ 1 mol N₂ Amount of H₂ Remaining in the Container = H₂ amount given H₂ amount USED= = x 2.02 g H₂ = 0.13366 g H₂ 1 mol H₂ 0.61802 g H₂ GIVEN 0.13366 g H₂ USED 0.48436 g of H₂--LEFT OVER = EXCESS
Transcribed Image Text:Write the balanced equation for the following situation. List the reaction type. Tell the amounts of every substance that remains in the container at the end of the reaction. Assume that all reactions go to completion. If only stoichiometry, tell how much of the excess reactant is used!!!! Reaction Type: a. Combination Reaction b. Decomposition Reaction c. Single Displacement / THIS IS ONE TYPE OF Oxidation Reduction Reaction d. Precipitation Reaction e. Gaseous Reaction f. Neutralization Reaction g. Combustion Reaction Follow the format used in the image. 1.95 g iron(III) chloride and 25.00 mL of a 0.250 M sodium hydroxide solution 2. N₂(g) + 3 H₂(g) → 2 NH3 (g) (This is LIMITING REACTANT: N₂ is the Limiting Reactant) Grams of Product (List the Product and the Amount): 0.75168 g NH3 Reaction Type: Combination or Single Displacement (which is also called Oxidation-Reduction) ? g NH3 = 61.802 cg N₂ x 1g N₂ LR 1 x 10² cg N₂ ? g NH3 = 61.802 cg H₂ x 1g H₂ 1 x 10² g H₂ x x 1 mol N₂ x 28.02 g N₂ 1 mol H₂ x 2.02 g H₂ 2 mol NH3 x 17.04 g NH3 = 0.75168 g NH3 ******* THEORETICAL YIELD 1 mol N₂ 1 mol NH3 2 mol NH3 x 17.04 g NH3 = 3.3756 g NH3 3 mol H₂ 1 mol NH3 How much N₂ remains in the vessel? You will use the LIMITING REACTANT and determine how much H₂ was USED in the RXN. ? g H₂ USED = 61.802 cg N₂ x 1g N₂ x 1 mol N₂ x 3 mol H₂ 1 x 10² cg N₂ 28.02 g N₂ 1 mol N₂ Amount of H₂ Remaining in the Container = H₂ amount given H₂ amount USED= = x 2.02 g H₂ = 0.13366 g H₂ 1 mol H₂ 0.61802 g H₂ GIVEN 0.13366 g H₂ USED 0.48436 g of H₂--LEFT OVER = EXCESS
Expert Solution
steps

Step by step

Solved in 3 steps with 3 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Stoichiometry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY
SEE MORE TEXTBOOKS