Write T for True or F for False by each question la lj. (d) – cos 2t + v3 sin 2t = 2 cos(2t – 27/3) (e) e(3+2i)t = e3t cos 2t. (f) The Wronskian of two functions f and g is W(f, g)(t) = t² – 4. If the initial conditions are assigned at to = 2, then f and g are linearly dependent.

L(cos3t) = S .a s2 +9 s+9 s2 – 9 s2+9 3.

Evaluate L {2t e2t sin (3t) – e3(1-1) + 3e-t sin (4t – 5)} |

Q1/ j-3j +2=e sinx to

ff2yx² + 2 sin(2x) + coś(ny)dA if R= [-2, 1] x [0, 1]

2C05 X+y Sin X-y 2. 2.

please send correct solution for Q 3 Using Demos Graphing

Q5: Show that S 2T Cos 30 5-4 cose 11 ㅠ 12

| cos(3r) dr 2.

(0,3) C1:x² + y² = 9. (-3,0) C2 (3,0) Figure 1 Based on Figure 1 and given that F = y² i + (3xy + 4x)j, answer the following questions. a) Determine whether the following statements are True (T) or False (F). Steps T/F i The r(t) for the equation C1 is r(t) = 3 cos t i + 3 sin t j. T ii Then, r'(t) = 3 sin t i – 3 cos t j. F iii Based on (i), the S, P dx + Q dy can be simplified as, S-27 sin30 + 54 cos?0 sin 0 + 36 cos 0 de F iv The limit of integration the f. P dx + Q dy is F f d0 The equation of the curve C2 is y= 0. vi By parametrizing the equation C2, the S, P dx + Q dy can be simplified as, Sc 3t dt vii The limit of integration for the P dx + Q dy is f de b) Use Green's theorem to calculate the work performed by the given vector F that moves around the curve C as shown in the Figure 1. (ans: 18+ 187)