Write code that prints: Ready! numVal ... 2 1 Go!Your code should contain a for loop. Print a newline after each number and after each line of text.Ex: If the input is:3the output is:Ready!321Go!1 import java.util.Scanner;23 public class ForLoops {4789101112 13 1414}public static void main (String [] args) {int numVal;int i;}Scanner inputnumVal =new Scanner(System.in);input.nextInt();=/* Your code goes here */

Your java program is given below as you required with an output screenshot.

Write code that prints: Ready! numVal ... 2 1 Go! Your code should contain a for loop. Print a newline after each number and after each line of text. Ex: If the input is: 3 the output is: Ready! 3 2 1 Go! 1 import java.util.Scanner; 3 public class ForLoops { L234567∞0 OHNE & 8 9 public static void main (String [] args) { int numVal; int i; 10 11 12 13 } 14} Scanner input = new Scanner(System.in); numVal = input.nextInt(); /* Your code goes here */

Write code that prints: Ready! numVal ... 2 1 Go! Your code should contain a for loop. Print a newline after each number and after each line of text. Ex: If the input is: 3 the output is: Ready! 3 2 1 Go! 1 import java.util.Scanner; 3 public class ForLoops { L234567∞0 OHNE & 8 9 public static void main (String [] args) { int numVal; int i; 10 11 12 13 } 14} Scanner input = new Scanner(System.in); numVal = input.nextInt(); /* Your code goes here */

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

1. Divisors: In a class Divisors.java, read in a maximum integer n and use nested loops to print a list of divisors for each of 1 through n as shown in the following transcript. Sample transcript (input underlined): Largest integer? 100 1: 1 2: 1 2 3: 1 3 4: 1 2 4 95: 1 5 19 95 96: 1 2 3 4 6 8 12 16 24 32 48 96 97: 1 97 98: 1 2 7 14 49 98 99: 1 3 9 11 33 99 100: 1 2 4 5 10 20 25 50 100
In c++ Write a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards, th backwards End each loop with a newline. Ex If courseGrades (7, 9, 11, 10), print: 7 9 11 10 10 11 9 7 Hint Use two for loops. Second loop starts with i=NUM VALS-1. (Notes) Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element array (int courseGrades(4) See 'How to Use zyBooks Also note: If the submitted code tries to access an invalid array element, such as courseGrades[9] for a 4-element array, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message 32344345730rity? 2 using namespace std; 3 4 int main() { 5 6 7 8 9 10 11 12 13 14 const int NUM VALS-4; int courseGrades [NUM VALS]; int i; for (i = 0; i > courseGrades[1]; } y Your solution goes here Y
please code in python You place a pawn at the top left corner of an n-by-n chess board, labeled (0,0). For each move, you have a choice: move the pawn down a single space, or move the pawn down one space and right one space. That is, if the pawn is at position (i,j), you can move the pawn to (i+1,j) or (i+1, j+1). Ask the user for the size of a chessboard, n (integer). Find the number of different paths starting from (0,0) that the pawn could take to reach each position on the chess board. For example, there are two different paths the pawn can take to reach (2,1). Look at the diagrams below to convince yourself of this. You can see the four paths that you can take by move 2. Start -> Move 1 -> Move 2 (0,0) -> (1,0) -> (2,1) (0,0) -> (1,0) -> (2,0) (0,0) -> (1,1) -> (2,1) (0,0) -> (1,1) -> (2,2) Print the board with the number of ways to reach each square labeled as shown below. For example: Enter a board size: 4 1 0 0 0 1 1 0 0 1 2 1 0 1 3 3 1
solve in java Integer numInput is read from input representing the number of integer values to be read next. Use a loop to read the remaining integer values from input. For each integer value read, output "Value read: " followed by the value. Then, output "Highest: " followed by the highest of the integer values read. End each output with a newline. Ex: If the input is: 3 220 -490 5 then the output is: Value read: 220 Value read: -490 Value read: 5 Highest: 220 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 import java.util.Scanner; public class HighestValues { publicstaticvoidmain(String[] args) { Scannerscnr=newScanner(System.in); intnumInput; intinputValue; inthighestVal=0; inti; numInput=scnr.nextInt(); /* Your code goes here */ } }
in java Write code that prints: firstNumber … 2 1Print a newline after each number. Ex: If the input is: 3 the output is: 3 2 1 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 import java.util.Scanner; public class ForLoops { publicstaticvoidmain (String [] args) { intfirstNumber; inti; Scannerinput=newScanner(System.in); firstNumber=input.nextInt(); for () { System.out.println(i); } } }
StringFun.java import java.util.Scanner; // Needed for the Scanner class 2 3 /** Add a class comment and @tags 4 5 */ 6 7 public class StringFun { /** * @param args not used 8 9 10 11 12 public static void main(String[] args) { Scanner in = new Scanner(System.in); System.out.print("Please enter your first name: "); 13 14 15 16 17 18 System.out.print("Please enter your last name: "); 19 20 21 //Output the welcome message with name 22 23 24 //Output the length of the name 25 26 27 //Output the username 28 29 30 //Output the initials 31 32 33 //Find and output the first name with switched characters 34 //All Done! } } 35 36 37
Review Loops Write a java program to ask three people three questions about name, number of courses, and number of credit hours. Also, print result in columns as below. Note: the input.nextInt() method reads only the integer value from input buffer.The "\n" is still staying in the input buffer. If you continue reading with input.nextLine(),you will receive the "\n" and CPU will not wait for any input. To fix this problem, you addthe statement input.nextLine() to flush out the "\n" from the input buffer.
Assign the size of userlnput to stringSize. Ex: if userlnput is "Hello", output is: Size of userInput: 1 import java.util.Scanner; 2 3 public class StringSize { public static void main (String [] args) { Scanner scnr = new Scanner(System.in); String userInput; int stringSize; 4 5 8 9. userInput scnr.nextLine(); %3D 10 11 /* Your solution goes here */ 12 13 System.out.println("Size of userInput: + stringSize); 14 15 return; } 16 17 }
Given string userString on one line, character charToFind on a second line, and integer strIndex on a third line, output "Found match" if the character at index strIndex of userString matches charToFind. Otherwise, output "No match". End with a newline. Ex: If the input is: warmth a 1 then the output is: Found match import java.util.Scanner; public class MatchingChar { public static void main(String[] args) { Scanner scnr = new Scanner(System.in); String userString; char charToFind; int strIndex; userString = scnr.nextLine(); charToFind = scnr.next().charAt(0); strIndex = scnr.nextInt(); /* Your code goes here */ } }
JAVA Language: Transpose Rotate. Question: Modify Transpose.encode() so that it uses a rotation instead of a reversal. That is, a word like “hello” should be encoded as “ohell” with a rotation of one character. (Hint: use a loop to append the letters into a new string) import java.util.*; public class TestTranspose { public static void main(String[] args) { String plain = "this is the secret message"; // Here's the message Transpose transpose = new Transpose(); String secret = transpose.encrypt(plain); System.out.println("\n ********* Transpose Cipher Encryption *********"); System.out.println("PlainText: " + plain); // Display the results System.out.println("Encrypted: " + secret); System.out.println("Decrypted: " + transpose.decrypt(secret));// Decrypt } } abstract class Cipher { public String encrypt(String s) { StringBuffer result = new…
Print the two strings, firstString and secondString, in alphabetical order. Assume the strings are lowercase. End with newline. Sample output: capes rabbits 1 import java.util.Scanner; 2 3 public class OrderStrings { public static void main (String [] args) { Scanner scnr = new Scanner(System.in); String firstString; String secondString; 4 6 7 8 firstString secondString scnr.next(); scnr.next(); 9. 10 11 12 /* Your solution goes here */ 13 14 } 15 }
Convert the following java code to C++ //LabProgram.javaimport java.util.Scanner;public class LabProgram {public static void main(String[] args) {//defining a Scanner to read input from the userScanner input = new Scanner(System.in);//reading the value for Nint N = input.nextInt();//creating a 1xN matrixint[] m1 = new int[N];//creating an NxN matrixint[][] m2 = new int[N][N];//creating a 1xN matrix to store the resultint[] result = new int[N];//looping and reading N integers into m1for (int i = 0; i < N; i++) {m1[i] = input.nextInt();}//looping from 0 to N-1for (int i = 0; i < N; i++) {//looping from 0 to N-1for (int j = 0; j < N; j++) {//reading an integer and storing it into m2 at position i,jm2[i][j] = input.nextInt();}}//multiply m1 and m2, store result in result//looping from 0 to N-1for (int i = 0; i < N; i++) {//looping from 0 to N-1for (int j = 0; j < N; j++) {//multiplying value at index j in m1 with value at j,i in m2, adding to current value at index i// on…