Write and evaluate the definite integral that represents the volume of the solid formed by revolving the region about the x-axis.

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Write and evaluate the definite integral that represents the volume of the solid formed by revolving the region about the x-axis.
### Calculating the Volume of a Solid of Revolution

**Problem Statement:**
Write and evaluate the definite integral that represents the volume of the solid formed by revolving the region about the x-axis.

Given functions:
\[ y = x^4 \]
\[ y = x^7 \]

**Graphical Representation:**
A graph is provided that shows the two functions \( y = x^4 \) and \( y = x^7 \). The region enclosed between these two curves, and between \( x = 0 \) and \( x = 1 \), is highlighted. This region is shaded to indicate that it will be revolved around the x-axis to form a solid. 

- The vertical axis is labeled \( y \).
- The horizontal axis is labeled \( x \).
- The important points of intersection are shown at \( x = 0 \) and \( x = 1 \). 

**Integration Setup:**
To find the volume of the solid formed by revolving the given region about the x-axis, the washer method is used. The volume \( V \) is given by the formula:

\[ V = \pi \int_{a}^{b} \left( R(x)^2 - r(x)^2 \right) dx \]

Where:
- \( R(x) = x^4 \) is the outer radius,
- \( r(x) = x^7 \) is the inner radius,
- The bounds of integration are \( a = 0 \) and \( b = 1 \).

Thus, the integral to be evaluated is:

\[ V = \pi \int_{0}^{1} \left( (x^4)^2 - (x^7)^2 \right) dx \]
\[ V = \pi \int_{0}^{1} \left( x^8 - x^{14} \right) dx \]

**Evaluating the Integral:**

\[ V = \pi \left[ \frac{x^9}{9} - \frac{x^{15}}{15} \right]_0^1 \]
\[ V = \pi \left( \frac{1^9}{9} - \frac{1^{15}}{15} \right) - \pi \left( \frac{0^9}{9} - \frac{0^{15}}{15} \right) \]
\[ V = \pi \left( \frac{1}{9
Transcribed Image Text:### Calculating the Volume of a Solid of Revolution **Problem Statement:** Write and evaluate the definite integral that represents the volume of the solid formed by revolving the region about the x-axis. Given functions: \[ y = x^4 \] \[ y = x^7 \] **Graphical Representation:** A graph is provided that shows the two functions \( y = x^4 \) and \( y = x^7 \). The region enclosed between these two curves, and between \( x = 0 \) and \( x = 1 \), is highlighted. This region is shaded to indicate that it will be revolved around the x-axis to form a solid. - The vertical axis is labeled \( y \). - The horizontal axis is labeled \( x \). - The important points of intersection are shown at \( x = 0 \) and \( x = 1 \). **Integration Setup:** To find the volume of the solid formed by revolving the given region about the x-axis, the washer method is used. The volume \( V \) is given by the formula: \[ V = \pi \int_{a}^{b} \left( R(x)^2 - r(x)^2 \right) dx \] Where: - \( R(x) = x^4 \) is the outer radius, - \( r(x) = x^7 \) is the inner radius, - The bounds of integration are \( a = 0 \) and \( b = 1 \). Thus, the integral to be evaluated is: \[ V = \pi \int_{0}^{1} \left( (x^4)^2 - (x^7)^2 \right) dx \] \[ V = \pi \int_{0}^{1} \left( x^8 - x^{14} \right) dx \] **Evaluating the Integral:** \[ V = \pi \left[ \frac{x^9}{9} - \frac{x^{15}}{15} \right]_0^1 \] \[ V = \pi \left( \frac{1^9}{9} - \frac{1^{15}}{15} \right) - \pi \left( \frac{0^9}{9} - \frac{0^{15}}{15} \right) \] \[ V = \pi \left( \frac{1}{9
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