Write an inequality relating the given side lengths, if possible. K LM and AB A 690 L M Choose the correct conclusion below. O A. LM> AB O B. LM = AB OC. LM « AB D. no conclusion

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Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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**Inequality of Side Lengths in Triangles**

The task is to write an inequality relating the given side lengths, LM and AB, if possible.

There are two triangles depicted: △KLM and △ABC. 

- **Triangle △KLM**:
  - Angle ∠LMK = 55°
  - Side LM is opposite this angle.

- **Triangle △ABC**:
  - Angle ∠BAC = 69°
  - Side AB is opposite this angle.

Both triangles have one marked equal side, indicating that segments LM and AC might be considered in comparing the triangles.

**Choose the correct conclusion below:**

- A. LM > AB
- B. LM = AB
- C. LM < AB
- D. no conclusion

**Analysis**:
Since angle ∠BAC (69°) is greater than angle ∠LMK (55°), the side opposite ∠BAC (i.e., side AB) will be longer than the side opposite ∠LMK (i.e., side LM) if the sides are indeed directly comparable.

**Conclusion**:
Select option C: LM < AB.
Transcribed Image Text:**Inequality of Side Lengths in Triangles** The task is to write an inequality relating the given side lengths, LM and AB, if possible. There are two triangles depicted: △KLM and △ABC. - **Triangle △KLM**: - Angle ∠LMK = 55° - Side LM is opposite this angle. - **Triangle △ABC**: - Angle ∠BAC = 69° - Side AB is opposite this angle. Both triangles have one marked equal side, indicating that segments LM and AC might be considered in comparing the triangles. **Choose the correct conclusion below:** - A. LM > AB - B. LM = AB - C. LM < AB - D. no conclusion **Analysis**: Since angle ∠BAC (69°) is greater than angle ∠LMK (55°), the side opposite ∠BAC (i.e., side AB) will be longer than the side opposite ∠LMK (i.e., side LM) if the sides are indeed directly comparable. **Conclusion**: Select option C: LM < AB.
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