Write an example of a function and solve whose derivative can be found by using the following rules: a) Product rule and special function differentiation rules b) Power rule, quotient rule, and chain rule c) Chain rule twice d) Implicit differentiation and special function differentiation rule I am attaching example use another examples but solution liek that

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Write an example of a function and solve whose derivative can be found by using the following rules: a) Product rule and special function differentiation rules b) Power rule, quotient rule, and chain rule c) Chain rule twice d) Implicit differentiation and special function differentiation rule I am attaching example use another examples but solution liek that
(a) PRODUCT RULE EXAMPLES:
f(x) = (3x²+4) (2x³-3x)
f'(X) = (3x² + 4) £x (2x³ =3x) + x ( 3X²+4) (2x³-3x)
d/dx (2x³-3x) = 6x² 3! (3x²+4) =GX
f'(x) = (3x²+4) (GX²-3) + (GX) (RX³-3x)
18x4-9x2 + 24x² -12 +12x" -18x²
[ƒ¹(x) = 30 x² - 3X²-/2
PUNCTION
SPECIAL A DIFFERENTIAL RULES:
LOENTITIES
d
dx
d
dx
d
ax
d
dx
G=0
n
*²
ex.
x
=e
n-l
Tin XECOSX
COS X = SHAX
b) POWER RULE.
f(x) = x²
f'(x) = 2x²
f(x)=2x
2+
EXAMPLES
QUOTIENT RULE:
f(x)= x² + 3x
xf4
|f'(x)=
dt
(ssint + 8cust)
& (5 sint) + & (&cost)
at
50 sint
+ &at cust
Scost
= 5cost
f'(x) = (x+4) (2x+3) - (X+9x) (1)
(x+4)²
2x+3x18x+12-X-3X
2
(x+4)
x² 18x+12
+-8 sint
(x+4)2
(x+2)(x+4)
(x+4)2
-ssin t
CHAIN RULT:
f(x) = (x²+1) ³
f'(x) = 3 (x²+1
f'(x) = 6x (x²+
Transcribed Image Text:(a) PRODUCT RULE EXAMPLES: f(x) = (3x²+4) (2x³-3x) f'(X) = (3x² + 4) £x (2x³ =3x) + x ( 3X²+4) (2x³-3x) d/dx (2x³-3x) = 6x² 3! (3x²+4) =GX f'(x) = (3x²+4) (GX²-3) + (GX) (RX³-3x) 18x4-9x2 + 24x² -12 +12x" -18x² [ƒ¹(x) = 30 x² - 3X²-/2 PUNCTION SPECIAL A DIFFERENTIAL RULES: LOENTITIES d dx d dx d ax d dx G=0 n *² ex. x =e n-l Tin XECOSX COS X = SHAX b) POWER RULE. f(x) = x² f'(x) = 2x² f(x)=2x 2+ EXAMPLES QUOTIENT RULE: f(x)= x² + 3x xf4 |f'(x)= dt (ssint + 8cust) & (5 sint) + & (&cost) at 50 sint + &at cust Scost = 5cost f'(x) = (x+4) (2x+3) - (X+9x) (1) (x+4)² 2x+3x18x+12-X-3X 2 (x+4) x² 18x+12 +-8 sint (x+4)2 (x+2)(x+4) (x+4)2 -ssin t CHAIN RULT: f(x) = (x²+1) ³ f'(x) = 3 (x²+1 f'(x) = 6x (x²+
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