Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Question
![### Writing the Equation of a Line
To find the equation of the line passing through the points \((-1, 2)\) and \((6, 3)\), follow these steps:
1. **Calculate the slope (m)**:
The slope of a line that passes through two points, \((x_1, y_1)\) and \((x_2, y_2)\), is calculated using the formula:
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
For the points \((-1, 2)\) and \((6, 3)\):
\[
m = \frac{3 - 2}{6 + 1} = \frac{1}{7}
\]
2. **Use the point-slope form to find the equation**:
The point-slope form of a line is:
\[
y - y_1 = m(x - x_1)
\]
Using the point \((-1, 2)\) and the slope \(m = \frac{1}{7}\):
\[
y - 2 = \frac{1}{7}(x + 1)
\]
3. **Simplify and convert to standard form**:
Expand and simplify the equation to convert it to standard form \(Ax + By = C\):
\[
y - 2 = \frac{1}{7}(x + 1)
\]
Multiply both sides by 7 to eliminate the fraction:
\[
7(y - 2) = x + 1
\]
Distribute and rearrange terms:
\[
7y - 14 = x + 1
\]
Combine like terms to get the standard form:
\[
-x + 7y = 15
\]
Or, multiplying through by -1 (to make \(x\) coefficient positive):
\[
x - 7y = -15
\]
Therefore, the equation of the line in standard form is:
\[
\boxed{x - 7y = -15}
\]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1437a046-45d0-460d-9d0e-bc1ea076a72e%2F90554615-d911-4416-b1c7-c0f22e17c821%2Fzrarpq3_processed.png&w=3840&q=75)
Transcribed Image Text:### Writing the Equation of a Line
To find the equation of the line passing through the points \((-1, 2)\) and \((6, 3)\), follow these steps:
1. **Calculate the slope (m)**:
The slope of a line that passes through two points, \((x_1, y_1)\) and \((x_2, y_2)\), is calculated using the formula:
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
For the points \((-1, 2)\) and \((6, 3)\):
\[
m = \frac{3 - 2}{6 + 1} = \frac{1}{7}
\]
2. **Use the point-slope form to find the equation**:
The point-slope form of a line is:
\[
y - y_1 = m(x - x_1)
\]
Using the point \((-1, 2)\) and the slope \(m = \frac{1}{7}\):
\[
y - 2 = \frac{1}{7}(x + 1)
\]
3. **Simplify and convert to standard form**:
Expand and simplify the equation to convert it to standard form \(Ax + By = C\):
\[
y - 2 = \frac{1}{7}(x + 1)
\]
Multiply both sides by 7 to eliminate the fraction:
\[
7(y - 2) = x + 1
\]
Distribute and rearrange terms:
\[
7y - 14 = x + 1
\]
Combine like terms to get the standard form:
\[
-x + 7y = 15
\]
Or, multiplying through by -1 (to make \(x\) coefficient positive):
\[
x - 7y = -15
\]
Therefore, the equation of the line in standard form is:
\[
\boxed{x - 7y = -15}
\]
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