Write an equation of the line passing through ( – 1,2) and (6,3). Give the answer in standard form. The equation of the line in standard form is

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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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### Writing the Equation of a Line

To find the equation of the line passing through the points \((-1, 2)\) and \((6, 3)\), follow these steps:

1. **Calculate the slope (m)**:
   The slope of a line that passes through two points, \((x_1, y_1)\) and \((x_2, y_2)\), is calculated using the formula:
   \[
   m = \frac{y_2 - y_1}{x_2 - x_1}
   \]
   For the points \((-1, 2)\) and \((6, 3)\):
   \[
   m = \frac{3 - 2}{6 + 1} = \frac{1}{7}
   \]

2. **Use the point-slope form to find the equation**:
   The point-slope form of a line is:
   \[
   y - y_1 = m(x - x_1)
   \]
   Using the point \((-1, 2)\) and the slope \(m = \frac{1}{7}\):
   \[
   y - 2 = \frac{1}{7}(x + 1)
   \]
   
3. **Simplify and convert to standard form**:
   Expand and simplify the equation to convert it to standard form \(Ax + By = C\):
   
   \[
   y - 2 = \frac{1}{7}(x + 1)
   \]
   Multiply both sides by 7 to eliminate the fraction:
   \[
   7(y - 2) = x + 1
   \]
   Distribute and rearrange terms:
   \[
   7y - 14 = x + 1
   \]
   Combine like terms to get the standard form:
   \[
   -x + 7y = 15
   \]
   Or, multiplying through by -1 (to make \(x\) coefficient positive):
   \[
   x - 7y = -15
   \]

Therefore, the equation of the line in standard form is:
\[
\boxed{x - 7y = -15}
\]
Transcribed Image Text:### Writing the Equation of a Line To find the equation of the line passing through the points \((-1, 2)\) and \((6, 3)\), follow these steps: 1. **Calculate the slope (m)**: The slope of a line that passes through two points, \((x_1, y_1)\) and \((x_2, y_2)\), is calculated using the formula: \[ m = \frac{y_2 - y_1}{x_2 - x_1} \] For the points \((-1, 2)\) and \((6, 3)\): \[ m = \frac{3 - 2}{6 + 1} = \frac{1}{7} \] 2. **Use the point-slope form to find the equation**: The point-slope form of a line is: \[ y - y_1 = m(x - x_1) \] Using the point \((-1, 2)\) and the slope \(m = \frac{1}{7}\): \[ y - 2 = \frac{1}{7}(x + 1) \] 3. **Simplify and convert to standard form**: Expand and simplify the equation to convert it to standard form \(Ax + By = C\): \[ y - 2 = \frac{1}{7}(x + 1) \] Multiply both sides by 7 to eliminate the fraction: \[ 7(y - 2) = x + 1 \] Distribute and rearrange terms: \[ 7y - 14 = x + 1 \] Combine like terms to get the standard form: \[ -x + 7y = 15 \] Or, multiplying through by -1 (to make \(x\) coefficient positive): \[ x - 7y = -15 \] Therefore, the equation of the line in standard form is: \[ \boxed{x - 7y = -15} \]
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