Write an equation in slope-intercept form for the line shown in the graph.

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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### Question 1

**Prompt:**
Write an equation in slope-intercept form for the line shown in the graph.

**Graph Description:**
The graph represents a coordinate plane with the x-axis and y-axis both ranging from -6 to 6. A line is graphed, passing through the points (0, -3) and (3, 3).

**Explanation:**
To write the equation of a line in slope-intercept form, we use the formula:

\[ y = mx + b \]

Where:
- \( m \) is the slope of the line
- \( b \) is the y-intercept (the value of \( y \) where the line crosses the y-axis)

1. **Identify the Slope (m):**
   The slope \( m \) is determined by the change in \( y \) divided by the change in \( x \) between two points on the line. Using the points (0, -3) and (3, 3):

   \[
   m = \frac{\text{change in } y}{\text{change in } x} = \frac{3 - (-3)}{3 - 0} = \frac{3 + 3}{3} = \frac{6}{3} = 2
   \]

2. **Identify the y-intercept (b):**
   The y-intercept \( b \) is the value of \( y \) where the line crosses the y-axis. From the graph, it is clear that the line crosses the y-axis at (0, -3). Thus, \( b = -3 \).

3. **Form the equation:**
   Using the slope \( m = 2 \) and y-intercept \( b = -3 \), the equation of the line in slope-intercept form is:

   \[
   y = 2x - 3
   \]

So, the equation for the line shown in the graph is:

\[
y = 2x - 3
\]
Transcribed Image Text:### Question 1 **Prompt:** Write an equation in slope-intercept form for the line shown in the graph. **Graph Description:** The graph represents a coordinate plane with the x-axis and y-axis both ranging from -6 to 6. A line is graphed, passing through the points (0, -3) and (3, 3). **Explanation:** To write the equation of a line in slope-intercept form, we use the formula: \[ y = mx + b \] Where: - \( m \) is the slope of the line - \( b \) is the y-intercept (the value of \( y \) where the line crosses the y-axis) 1. **Identify the Slope (m):** The slope \( m \) is determined by the change in \( y \) divided by the change in \( x \) between two points on the line. Using the points (0, -3) and (3, 3): \[ m = \frac{\text{change in } y}{\text{change in } x} = \frac{3 - (-3)}{3 - 0} = \frac{3 + 3}{3} = \frac{6}{3} = 2 \] 2. **Identify the y-intercept (b):** The y-intercept \( b \) is the value of \( y \) where the line crosses the y-axis. From the graph, it is clear that the line crosses the y-axis at (0, -3). Thus, \( b = -3 \). 3. **Form the equation:** Using the slope \( m = 2 \) and y-intercept \( b = -3 \), the equation of the line in slope-intercept form is: \[ y = 2x - 3 \] So, the equation for the line shown in the graph is: \[ y = 2x - 3 \]
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