Write a valid Lewis structure of the compound with the elemental composition C3H7I that gives the following ¹H-NMR spectrum. EXPLAIN your reasoning. .A. C3H7I 7 4.5 4.3 5 S 2.0 1.8 4 μ (ppm) 3 TMS
Write a valid Lewis structure of the compound with the elemental composition C3H7I that gives the following ¹H-NMR spectrum. EXPLAIN your reasoning. .A. C3H7I 7 4.5 4.3 5 S 2.0 1.8 4 μ (ppm) 3 TMS
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:**NMR Spectrum Analysis for Compound C₃H₇I**
This document presents a proton NMR (¹H NMR) spectrum for a compound with the molecular formula C₃H₇I. The goal is to write a valid Lewis structure for this compound and explain the reasoning behind it based on the NMR data provided.
### NMR Spectrum Description:
- **Chemical Shifts (δ in ppm):**
- **4.5 to 4.3 ppm:** A multiplet appears in this region, likely indicating protons near an electronegative atom such as iodine.
- **2.0 ppm:** A singlet appears, suggesting protons in an environment with no neighboring protons (e.g., methyl group).
- **1.8 ppm:** Another singlet, indicating similar environmental conditions as the 2.0 ppm signal but involving different protons.
- **Integration:**
- The integration curve shows the relative area under each peak, representing the number of hydrogens contributing to each signal.
- **TMS (Tetramethylsilane) Reference:**
- The peak at 0 ppm is not visible here but would typically serve as the reference for chemical shift values.
### Explanation:
Based on typical chemical shifts and splitting patterns, this spectrum provides insights into the structure:
- **4.5 to 4.3 ppm Region:** The presence of a multiplet indicates coupling with neighboring protons. This suggests an environment where protons are near a halogen (iodine), possibly attached to a carbon in a primary or secondary position.
- **2.0 and 1.8 ppm Regions:** The singlets here suggest isolated methyl groups or protons attached to carbons with no nearby protons for splitting.
### Conclusion:
The spectral data suggest the compound could be either 1-iodopropane (with coupling seen if iodine is attached at one end) or 2-iodopropane (more likely if the protons are more isolated). Consider the neighboring carbon environment and use additional spectroscopic or chemical information to finalize the structure decision.
**Note to Educators:**
This exercise helps students apply NMR analysis to determine molecular structure, assessing both chemical environment and proton coupling.
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