Write a system of equations that represents the situation. Then, solve the system using the inverse of a matrix. A farmer constructed a chicken coop out of chicken wire, wood, and plywood. The chicken wire cost $2 per square foot, the wood $10 per square foot, and the plywood $5 per square foot. The farmer spent a total of $47, and the total amount of materials used was 11 ft2. He used 3 ft more chicken wire than plywood. How much of each material did the farmer use? chicken wire ft2 wood ft2 plywood ft2 Additional Materials MeBook

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Educational Text: Solving Systems of Equations with Matrices**

**Problem Statement:**

A farmer constructed a chicken coop using three different materials: chicken wire, wood, and plywood. The cost of the materials is as follows:

- Chicken wire: $2 per square foot
- Wood: $10 per square foot
- Plywood: $5 per square foot

The farmer spent a total of $47, and the total area covered by the materials was 11 square feet. Additionally, the farmer used 3 square feet more of chicken wire than plywood. We need to determine how much of each material the farmer used.

**Questions:**

1. How many square feet of chicken wire did the farmer use?
2. How many square feet of wood did the farmer use?
3. How many square feet of plywood did the farmer use?

**Solution Approach:**

To find the solution, we need to set up a system of equations based on the given information and solve it using the inverse of a matrix. Let's define:

- \( x \): square feet of chicken wire
- \( y \): square feet of wood
- \( z \): square feet of plywood

**Equations:**

1. From the cost information:
\[ 2x + 10y + 5z = 47 \]

2. From the total area of materials:
\[ x + y + z = 11 \]

3. From the additional information about chicken wire:
\[ x = z + 3 \]

These equations can be solved using matrices for a clear solution.
Transcribed Image Text:**Educational Text: Solving Systems of Equations with Matrices** **Problem Statement:** A farmer constructed a chicken coop using three different materials: chicken wire, wood, and plywood. The cost of the materials is as follows: - Chicken wire: $2 per square foot - Wood: $10 per square foot - Plywood: $5 per square foot The farmer spent a total of $47, and the total area covered by the materials was 11 square feet. Additionally, the farmer used 3 square feet more of chicken wire than plywood. We need to determine how much of each material the farmer used. **Questions:** 1. How many square feet of chicken wire did the farmer use? 2. How many square feet of wood did the farmer use? 3. How many square feet of plywood did the farmer use? **Solution Approach:** To find the solution, we need to set up a system of equations based on the given information and solve it using the inverse of a matrix. Let's define: - \( x \): square feet of chicken wire - \( y \): square feet of wood - \( z \): square feet of plywood **Equations:** 1. From the cost information: \[ 2x + 10y + 5z = 47 \] 2. From the total area of materials: \[ x + y + z = 11 \] 3. From the additional information about chicken wire: \[ x = z + 3 \] These equations can be solved using matrices for a clear solution.
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