In C programWrite a recursive function count_digits()that counts all the digits in a string.This would be similar to function count()we covered during our last lecture,which counts the number of occurrences of a character chin a string str.Hint: Use function isdigit(str[0])to find out if str[0]is numeric. ```cint count(char ch, const char *str){ int ans; if (str[0] == '\0') /* simple case */ ans = 0; else /* redefine problem using recursion */ if (ch == str[0]) /* first character must be counted */ ans = 1 + count(ch, &str[1]); else /* first character is not counted */ ans = count(ch, &str[1]); return (ans);}```**Explanation:**This C function, `count`, recursively counts the occurrences of a specific character `ch` in a string `str`.- **Base Case:** If the first character of the string is the null character `'\0'`, it sets `ans` to 0, which means the end of the string has been reached.- **Recursive Case:** - If the first character of the string is equal to `ch`, it counts this character (adds 1) and makes a recursive call to `count` with the next character in the string. - If the first character is not equal to `ch`, it simply makes a recursive call, ignoring the first character.- **Return Value:** The function returns the total count of `ch` in the string.

Please find the answer below :Required Function : int count_digits(const char *myString){ //Declaring required variables int res; if (myString[0]=='\0') res=0; else //Checking if digit if(isdigit(myString[0])) res=1+count_digits(&myString[1]); else //Recursive call to the function res= count_digits(&myString[1]); //Return the result return res;} Testing in Main Program : Executable Code: #include <stdio.h>#include <ctype.h> //Required function int count_digits(const char *myString){ //Declaring required variables int res; if (myString[0]=='\0') res=0; else //Checking if digit if(isdigit(myString[0])) res=1+count_digits(&myString[1]); else //Recursive call to the function res= count_digits(&myString[1]); //Return the result return res;} //Testing int main() { //Declaring string char myString[50]; //Prompting for input printf("Enter any String : "); scanf("%s",myString); //Calling the function and printing the result int result = count_digits(myString); printf("No of digits: %d",result); return 0;} Sample Output : Please do rate the answer if it is helpful thanks :)