Write a query to output the apartments whose prices are greater than the average and are also not rented, sorted by the 'Price' column.
Write a query to output the apartments whose prices are greater than the average and are also not rented, sorted by the 'Price' column.
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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![### Problem Statement: Apartments Information Query
In this exercise, you will be required to write an SQL query to output details about certain apartments based on specific criteria. The provided table consists of three columns: Apartment Name, Address, Price, and Rental Status.
Below is the table representing the data:
| | Apartment Name | Address | Price | Rental Status |
|---|----------------|--------------------------|-------|---------------|
| 3 | Moretown | 3757 Wines Lane | 700 | Not rented |
| 4 | Owatonna | 314 Pritchard Court | 500 | Rented |
| 5 | Grayslake | 3234 Cunningham Court | 600 | Rented |
| 6 | Great Neck | 1927 Romines Mill Road | 900 | Not rented |
### Task:
Write a query to output the apartments whose prices are **greater than the average** and are also **not rented**, sorted by the `Price` column.
#### Note:
- Recall the `AVG` keyword to compute the average price.
- Ensure the final results are sorted in ascending order of price.
#### Instructions:
1. Calculate the average price of all the apartments.
2. Select apartments that meet the following criteria:
- Price is greater than the average.
- The rental status is "Not rented".
3. Order the result by the `Price` column.
Once you have formulated the SQL query based on the above requirements, click on the "Start Solving" button to test your solution.
![Graph] The table above is part of the problem statement and provides necessary details required to solve the exercise.
**Example SQL Query:**
```sql
SELECT Apartment Name, Address, Price, Rental Status
FROM Apartments
WHERE Price > (SELECT AVG(Price) FROM Apartments)
AND Rental Status = 'Not rented'
ORDER BY Price;
```
**Happy Query Writing!**](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fae98b63a-c1e0-40a0-8ef8-c296ebcafc68%2F819f9165-b41d-49a5-9d3d-943d84dac287%2F0pwilfb_processed.png&w=3840&q=75)
Transcribed Image Text:### Problem Statement: Apartments Information Query
In this exercise, you will be required to write an SQL query to output details about certain apartments based on specific criteria. The provided table consists of three columns: Apartment Name, Address, Price, and Rental Status.
Below is the table representing the data:
| | Apartment Name | Address | Price | Rental Status |
|---|----------------|--------------------------|-------|---------------|
| 3 | Moretown | 3757 Wines Lane | 700 | Not rented |
| 4 | Owatonna | 314 Pritchard Court | 500 | Rented |
| 5 | Grayslake | 3234 Cunningham Court | 600 | Rented |
| 6 | Great Neck | 1927 Romines Mill Road | 900 | Not rented |
### Task:
Write a query to output the apartments whose prices are **greater than the average** and are also **not rented**, sorted by the `Price` column.
#### Note:
- Recall the `AVG` keyword to compute the average price.
- Ensure the final results are sorted in ascending order of price.
#### Instructions:
1. Calculate the average price of all the apartments.
2. Select apartments that meet the following criteria:
- Price is greater than the average.
- The rental status is "Not rented".
3. Order the result by the `Price` column.
Once you have formulated the SQL query based on the above requirements, click on the "Start Solving" button to test your solution.
![Graph] The table above is part of the problem statement and provides necessary details required to solve the exercise.
**Example SQL Query:**
```sql
SELECT Apartment Name, Address, Price, Rental Status
FROM Apartments
WHERE Price > (SELECT AVG(Price) FROM Apartments)
AND Rental Status = 'Not rented'
ORDER BY Price;
```
**Happy Query Writing!**
Transcribed Image Text:## Apartments
You want to rent an apartment and have the following table named **Apartments**:
| id | city | address | price | status |
|----|-----------|-----------------------|-------|------------|
| 1 | Las Vegas | 732 Hall Street | 1000 | Not rented |
| 2 | Marlboro | 985 Huntz Lane | 800 | Not rented |
| 3 | Moretown | 3757 Wines Lane | 700 | Not rented |
| 4 | Owatonna | 314 Pritchard Court | 500 | Rented |
To start solving this problem, click on the button below:
**START SOLVING**
---
This table lists various apartments that are available for rent, along with their respective details. Each apartment is identified by an `id` and includes information about the `city`, `address`, `price`, and `status` (whether it is currently rented or not).
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