Write a program in C to demonstrate the use of &(address of) and *(value at address) operator. Expected Output : Pointer & and operator : Demonstrate the use of m = 300 fx = 300.600006 cht = z Using & operator : address of m = 0x7ffda2eeeec8 address of fx = 0x7ffda2eeeecc address of cht = 0x7ffda2eeeec7 Using & and * operator : value at address of m = 300 value at address of fx = 300.600 006 value at address of cht = z Using only pointer variable : address of m = 0x7ffda2eeeec8 address of fx = 0x7ffda2eeeecc address of cht = 0x7ffda2eeeec7 Using only pointer operator : value at address of m = 300 value at address of fx= 300.6000 06 value at address of cht= z

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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Write a program in C to demonstrate
the use of &(address of) and *(value
at address) operator.
Expected Output:
Pointer Demonstrate the use of
& and operator :
m = 300
fx = 300.600006
cht = z
Using & operator :
address of m=0x7ffda2eeeec8
address of fx = 0x7ffda2eeeecc
address of cht=0x7ffda2eeeec7
Using & and * operator :
value at address of m = 300
value at address of fx = 300.600
006
value at address of cht = z
Using only pointer variable :
address of m = 0x7ffda2eeeec8
address of fx = 0x7ffda2eeeecc
address of cht = 0x7ffda2eeeec7
Using only pointer operator :
value at address of m = 300
value at address of fx= 300.6000
06
value at address of cht= z
Transcribed Image Text:Write a program in C to demonstrate the use of &(address of) and *(value at address) operator. Expected Output: Pointer Demonstrate the use of & and operator : m = 300 fx = 300.600006 cht = z Using & operator : address of m=0x7ffda2eeeec8 address of fx = 0x7ffda2eeeecc address of cht=0x7ffda2eeeec7 Using & and * operator : value at address of m = 300 value at address of fx = 300.600 006 value at address of cht = z Using only pointer variable : address of m = 0x7ffda2eeeec8 address of fx = 0x7ffda2eeeecc address of cht = 0x7ffda2eeeec7 Using only pointer operator : value at address of m = 300 value at address of fx= 300.6000 06 value at address of cht= z
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