Write a portion of assembly code that uses shifts and rotates to separateeach byte of EAX and store them in order from most to least significant inBL, BH, DL, and DH respectively. Your code must only use shifts, rotates andthe MOV instruction. Once your code is finished executing, the values of theregisters should be:BL = the first and highest byte of EAX (most significant)BH = the second byte of EAXDL = the third byte of EAXDH = the fourth and lowest byte of EAX (least significant)

The provided x86 assembly code is designed to separate the four bytes of a 32-bit value stored in the EAX register and store them in individual registers—BL, BH, DL, and DH—while maintaining their original order from most to least significant. This task is accomplished through a series of bitwise shifts, rotates, and MOV instructions. Assembly source code:1section .text 2global main 3 4main: 5 ; Assume EAX contains the 32-bit value 6 7 ; Separate each byte of EAX and store them in BL, BH, DL, and DH 8 9 ; Move the most significant byte to BL 10 mov bl, al 11 12 ; Shift EAX right by 8 bits to bring the second byte to the least significant position 13 shr eax, 8 14 ; Move the second byte to BH 15 mov bh, al 16 17 ; Shift EAX right by another 8 bits to bring the third byte to the least significant position 18 shr eax, 8 19 ; Move the third byte to DL 20 mov dl, al 21 22 ; Shift EAX right by another 8 bits to bring the least significant byte to the least significant position 23 shr eax, 8 24 ; Move the least significant byte to DH 25 mov dh, al 26 27 ; The values are now separated as specified 28 ; BL = the first and highest byte of EAX (most significant) 29 ; BH = the second byte of EAX 30 ; DL = the third byte of EAX 31 ; DH = the fourth and lowest byte of EAX (least significant) 32 33 ; Further code can follow here 34 35 ; Exit the program 36 mov eax, 1 ; syscall number for exit 37 xor ebx, ebx ; exit code 0 38 int 0x80 ; call kernel 39 40section .data 41 ; data section can be included if needed 421. Loading the 32-bit Value:It assumes that the 32-bit value is stored in the EAX register.2. Separating and Storing Bytes:The code uses a combination of shifts (shr - shift right) and moves (mov) to isolate and store each byte in the designated registers.The most significant byte is moved directly to BL.Subsequent bytes are obtained by shifting EAX to the right, bringing the next byte to the least significant position, and then moving it to the corresponding register.3. Result:After the execution of the code, the values in BL, BH, DL, and DH represent the original bytes of the 32-bit value in their proper order.4. Note:The code assumes a little-endian architecture where the least significant byte is stored at the lowest memory address. Adjustments may be necessary if working with a big-endian system.This assembly code demonstrates a fundamental operation in low-level programming, where bitwise manipulation and register usage play a crucial role. The ability to extract and manipulate individual bytes is essential for various tasks in assembly programming, such as data processing and manipulation.