Write a net ionic equation to show that triethylamine, (C2H5)3N, behaves as a Bronsted-Lowry base in water. BL base BL acid BL acid BL base H2O

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**Transcription for Educational Website**

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**Title:** Understanding Triethylamine as a Bronsted-Lowry Base

**Objective:** To write a net ionic equation demonstrating how triethylamine, \((\text{C}_2\text{H}_5)_3\text{N}\), functions as a Bronsted-Lowry base in water.

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**Instruction:**

Fill in the boxes below to complete the net ionic equation for the reaction of triethylamine in water.

**Equation Template:**

\[ 
\text{BL base} \square + \text{BL acid} \, \text{H}_2\text{O} \rightarrow \text{BL acid} \square + \text{BL base} \square 
\]

**Explanation:**

- **BL base (Box 1):** This represents the Bronsted-Lowry base in the reaction, which should be triethylamine, \((\text{C}_2\text{H}_5)_3\text{N}\).
  
- **BL acid (Box 2):** Water (\(\text{H}_2\text{O}\)) acts as the Bronsted-Lowry acid in this scenario.

- **Resultant BL acid (Box 3):** Following the base's acceptance of a proton, the resultant should be the conjugate acid of triethylamine.

- **Resultant BL base (Box 4):** After donating a proton, the resultant is the conjugate base formed from water.

**Concepts to Explore:**

- Define and explain Bronsted-Lowry acid-base theory.
- Discuss the role of donor and acceptor molecules in acid-base reactions.
- Explore the relationship between acids and their conjugate bases and bases and their conjugate acids.

**Application:**

This exercise helps understand how organic bases like triethylamine behave in aqueous solutions and reinforces the concepts of the Bronsted-Lowry acid-base theory.

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Transcribed Image Text:**Transcription for Educational Website** --- **Title:** Understanding Triethylamine as a Bronsted-Lowry Base **Objective:** To write a net ionic equation demonstrating how triethylamine, \((\text{C}_2\text{H}_5)_3\text{N}\), functions as a Bronsted-Lowry base in water. --- **Instruction:** Fill in the boxes below to complete the net ionic equation for the reaction of triethylamine in water. **Equation Template:** \[ \text{BL base} \square + \text{BL acid} \, \text{H}_2\text{O} \rightarrow \text{BL acid} \square + \text{BL base} \square \] **Explanation:** - **BL base (Box 1):** This represents the Bronsted-Lowry base in the reaction, which should be triethylamine, \((\text{C}_2\text{H}_5)_3\text{N}\). - **BL acid (Box 2):** Water (\(\text{H}_2\text{O}\)) acts as the Bronsted-Lowry acid in this scenario. - **Resultant BL acid (Box 3):** Following the base's acceptance of a proton, the resultant should be the conjugate acid of triethylamine. - **Resultant BL base (Box 4):** After donating a proton, the resultant is the conjugate base formed from water. **Concepts to Explore:** - Define and explain Bronsted-Lowry acid-base theory. - Discuss the role of donor and acceptor molecules in acid-base reactions. - Explore the relationship between acids and their conjugate bases and bases and their conjugate acids. **Application:** This exercise helps understand how organic bases like triethylamine behave in aqueous solutions and reinforces the concepts of the Bronsted-Lowry acid-base theory. ---
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