In C++ Write a functionvoid display triangle (int n, char direction) {..}That takes an integer and a character as parameters. If the character is 'i' (for increasing), it displaysa triangle of increasing '*'. If the character is 'd' (for decreasing), it displays a triangle ofdecreasing '*'. (Hint: use a nested for loop to display).Example: display (3, 'i') displaysand display (3, 'd') displays***Incorporate the function in a program that asks the user to enter the size and direction of the triangle, thencalls the function.

Answered: Write a function void display triangle…

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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Question

In C++

Write a function
void display triangle (int n, char direction) {..}
That takes an integer and a character as parameters. If the character is 'i' (for increasing), it displays
a triangle of increasing '*'. If the character is 'd' (for decreasing), it displays a triangle of
decreasing '*'. (Hint: use a nested for loop to display).
Example: display (3, 'i') displays
and display (3, 'd') displays
***
Incorporate the function in a program that asks the user to enter the size and direction of the triangle, then
calls the function.

Expert Solution

Step 1: Providing Introduction

We will define a function named display_triangle in this C++ program, which accepts two parameters: a character direction and an integer called n. The function will show an asterisk triangle (*) based on the direction that is supplied ('i' for increasing or 'd' for decreasing). This function will also be included in a program that asks the user to specify the triangle's size and orientation before invoking the display_triangle function in solution.

Please refer to the following steps for the complete solution to the problem above.