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Write a function that will calculate the sum of all the numbers multiple of 3 from N down to 1 using recursion. HINT: SAMPLE ALGORITHM int computeTotal(int n) { /1. declare a variable sum and initialize it to 0 to add all nos that are multiple l/of 3 1/2. test if n is equal to 0 I/ if true return n 1/3. else { //tests if n is divisible by 3 //if true test if(sum==0) sum=n; return sum+= computeTotal(n-1);

Write a function that will calculate the sum of all the numbers multiple of 3 from N down to 1 using recursion. HINT: SAMPLE ALGORITHM int computeTotal(int n) { /1. declare a variable sum and initialize it to 0 to add all nos that are multiple l/of 3 1/2. test if n is equal to 0 I/ if true return n 1/3. else { //tests if n is divisible by 3 //if true test if(sum==0) sum=n; return sum+= computeTotal(n-1);

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Write a C program

Write a function that will calculate the sum of all the numbers multiple of 3 from N down to 1 using recursion. HINT: SAMPLE ALGORITHM int computeTotal(int n) { /1. declare a variable sum and initialize it to 0 to add all nos that are multiple //of 3 /12. test if n is equal to 0 // if true return n //3. else { /tests if n is divisible by 3 //if true test if(sum==0) sum=n; return sum+= computeTotal(n-1); To pass the test you will get these results Test Input Expected Got printf("%d", computeTotal (10)); 10 18 18 printf("%d", computeTotal (20)); 20 63 63 printf ("&d", computeTotal (30)); 30 165 165 printf("%d", computeTotal (35)); 35 198 198
Transcribed Image Text:Write a function that will calculate the sum of all the numbers multiple of 3 from N down to 1 using recursion. HINT: SAMPLE ALGORITHM int computeTotal(int n) { /1. declare a variable sum and initialize it to 0 to add all nos that are multiple //of 3 /12. test if n is equal to 0 // if true return n //3. else { /tests if n is divisible by 3 //if true test if(sum==0) sum=n; return sum+= computeTotal(n-1); To pass the test you will get these results Test Input Expected Got printf("%d", computeTotal (10)); 10 18 18 printf("%d", computeTotal (20)); 20 63 63 printf ("&d", computeTotal (30)); 30 165 165 printf("%d", computeTotal (35)); 35 198 198
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