Write a function named `vectorSum(11, 12) that takes two lists of numbers and adds the numbers in l2 on 11, one by one. If 12 is shorter than 11, then 12 recycles from the beginning once it is over. If 12 is longer than 11, then only the first part of 12 that matches the length of l1 is considered. Your function must return the summed up resulting list. For example, vectorSum ( [1,2,3,4,5], [1, 2,3]) returns [2,4,6,5,7] because: 1,2,3,4,5 + + + + + 1,2,3,1,2 -> Here, 12 recycles from the beginning = = = = = 2,4,6,5,7 vectorSum ( [1, 2,3], [1,2,3,4,5]) returns [2,4,6] because: 1,2,3 + + + 1,2,3,4,5 -> Here, only the first 3 items of 12 are used = = = 2,4,6 vectorSum( [1,2,3,4,5], [1,2,1,2,1]) returns [2,4,4,6,6] because: 1,2,3,4,5 + + + + + 1,2,1,2,1 -> Here, length of 12 matches the length of 11 = = = = = 2,4,4,6,6 + es+ 1 And 1a

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solve  python please

Write a function named `vectorSum(11, 12) that takes two
lists of numbers and adds the numbers in l2 on 11, one by one.
If 12 is shorter than 11, then 12 recycles from the beginning
once it is over. If 12 is longer than 11, then only the first part
of 12 that matches the length of l1 is considered. Your function
must return the summed up resulting list. For example,
vectorSum ( [1,2,3,4,5], [1, 2,3]) returns [2,4,6,5,7] because:
1,2,3,4,5
+ + + + +
1,2,3,1,2
-> Here, 12 recycles from the beginning
= = = = =
2,4,6,5,7
vectorSum ( [1, 2,3], [1,2,3,4,5]) returns [2,4,6] because:
1,2,3
+ + +
1,2,3,4,5
-> Here, only the first 3 items of 12 are used
= = =
2,4,6
vectorSum ([1, 2,3,4,5], [1, 2,1,2,1]) returns [2,4,4,6,6] because:
1,2,3,4,5
+ + + + +
1,2,1, 2,1
-> Here, length of 12 matches the length of 11
= = = = =
2,4,4,6,6
You can assume that 11 and 12 are not empty.
def vectorSum (11, 12):
# remove the following line to solve this question
return
Transcribed Image Text:Write a function named `vectorSum(11, 12) that takes two lists of numbers and adds the numbers in l2 on 11, one by one. If 12 is shorter than 11, then 12 recycles from the beginning once it is over. If 12 is longer than 11, then only the first part of 12 that matches the length of l1 is considered. Your function must return the summed up resulting list. For example, vectorSum ( [1,2,3,4,5], [1, 2,3]) returns [2,4,6,5,7] because: 1,2,3,4,5 + + + + + 1,2,3,1,2 -> Here, 12 recycles from the beginning = = = = = 2,4,6,5,7 vectorSum ( [1, 2,3], [1,2,3,4,5]) returns [2,4,6] because: 1,2,3 + + + 1,2,3,4,5 -> Here, only the first 3 items of 12 are used = = = 2,4,6 vectorSum ([1, 2,3,4,5], [1, 2,1,2,1]) returns [2,4,4,6,6] because: 1,2,3,4,5 + + + + + 1,2,1, 2,1 -> Here, length of 12 matches the length of 11 = = = = = 2,4,4,6,6 You can assume that 11 and 12 are not empty. def vectorSum (11, 12): # remove the following line to solve this question return
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