Write a function named repeat that accepts a string (as a char*) and a number of repetitions as parameters and returns a heap-allocated string representing the parameter string concatenated that many times. For example, the call repeat("hello", 3) returns a new string "hellohellohello". If the number of repetitions is 0 or less, an empty string ("") should be returned. (You do not need to free any memory.) 1 char* repeat (char*s1, int repetitions ){ 2 if (repetitions <= Ø) { return ""; Jelse{ char* a = (char*) calloc(repetitions, sizeof(s1)); 3 4 5

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Answer the following in c? 

Write a function named repeat that accepts a string (as a char+) and a number of repetitions as
parameters and returns a heap-allocated string representing the parameter string concatenated that
many times. For example, the call repeat ("hello", 3) returns a new string
"hellohellohello". If the number of repetitions is 0 or less, an empty string ("") should be
returned. (You do not need to free any memory.)
1 char* repeat (char*s1, int repetitions ){
if (repetitions <= Ø) {
2
3
return
4
}else{
char* a = (char*) calloc(repetitions, sizeof (s1));
for ( int i = 1; i <= repetitions ; i++){
strcat (a, s1);
7
8
return a;
10
11
12 }
14
N 3 4
Transcribed Image Text:Write a function named repeat that accepts a string (as a char+) and a number of repetitions as parameters and returns a heap-allocated string representing the parameter string concatenated that many times. For example, the call repeat ("hello", 3) returns a new string "hellohellohello". If the number of repetitions is 0 or less, an empty string ("") should be returned. (You do not need to free any memory.) 1 char* repeat (char*s1, int repetitions ){ if (repetitions <= Ø) { 2 3 return 4 }else{ char* a = (char*) calloc(repetitions, sizeof (s1)); for ( int i = 1; i <= repetitions ; i++){ strcat (a, s1); 7 8 return a; 10 11 12 } 14 N 3 4
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