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write a computer program that uses newtons method to find the root of a given function. and  apply this program to find the root of the followig functions,  using X0 as given . stop the iteration when the error as estimated by  |Xn+1- Xn| is less than 10-6 . compare to your result for bisection. (a)  f(x)=1-2xe-×/2 , X0=0; (b)  f(X)=5-x-1, x0=1/4; (c)  f(x)=x3-2x-5, x0=2; (d)  f(x)=ex-2, x0=1; (e)  f(x)=x-ex, x0=1; (f)  f(x)=x6 - x -1, x0=1; (g)  f(x)=x2 -sin x, x0=1/2; (h)  f(x)=x3 - 2, x0=1; (i)  f(x)=x+ tan x, x0=3; (j)  f(x)=2 - x-1lnx , x0=1/3

write a computer program that uses newtons method to find the root of a given function. and  apply this program to find the root of the followig functions,  using X0 as given . stop the iteration when the error as estimated by  |Xn+1- Xn| is less than 10-6 . compare to your result for bisection. (a)  f(x)=1-2xe-×/2 , X0=0; (b)  f(X)=5-x-1, x0=1/4; (c)  f(x)=x3-2x-5, x0=2; (d)  f(x)=ex-2, x0=1; (e)  f(x)=x-ex, x0=1; (f)  f(x)=x6 - x -1, x0=1; (g)  f(x)=x2 -sin x, x0=1/2; (h)  f(x)=x3 - 2, x0=1; (i)  f(x)=x+ tan x, x0=3; (j)  f(x)=2 - x-1lnx , x0=1/3

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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write a computer program that uses newtons method to find the root of a given function. and  apply this program to find the root of the followig functions,  using X0 as given . stop the iteration when the error as estimated by  |Xn+1- Xn| is less than 10-6 . compare to your result for bisection.
(a)  f(x)=1-2xe-×/2 , X0=0;

(b)  f(X)=5-x-1, x0=1/4;

(c)  f(x)=x3-2x-5, x0=2;

(d)  f(x)=ex-2, x0=1;

(e)  f(x)=x-ex, x0=1;

(f)  f(x)=x6 - x -1, x0=1;

(g)  f(x)=x2 -sin x, x0=1/2;

(h)  f(x)=x3 - 2, x0=1;

(i)  f(x)=x+ tan x, x0=3;

(j)  f(x)=2 - x-1lnx , x0=1/3;

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