Write a C++ program to implement the LCS algorithm covered in class for finding the Longest Common Subsequence (LCS) of two sequences. Provide comprehensive comments and explanations within your code to elucidate the logic and implementation of the dynamic programming approach. Note that LCS is different from a common substring. Test your program with the following two cases to verify the correctness of your implementation: Test Case 1: Given two sequences X and Y: X= (A, B, C, B, D, A, B) and Y = (B, D, C, A, B, A) Test Case 2: Given two gene sequences S1 and S2: S₁ = ACCGGTCGAGTGCGCGGAAGCCGGCCGAA S₂ = GTCGTTCGGAATGCCGTTGCTCTGTAAA

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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Write a C++ program to implement the LCS algorithm covered in class for finding the Longest
Common Subsequence (LCS) of two sequences. Provide comprehensive comments and
explanations within your code to elucidate the logic and implementation of the dynamic
programming approach. Note that LCS is different from a common substring. Test your program
with the following two cases to verify the correctness of your implementation:
Test Case 1:
Given two sequences X and Y:
X= (A, B, C, B, D, A, B) and Y = (B, D, C, A, B, A)
Test Case 2:
Given two gene sequences S1 and S2:
S₁ = ACCGGTCGAGTGCGCGGAAGCCGGCCGAA
S₂ = GTCGTTCGGAATGCCGTTGCTCTGTAAA
Transcribed Image Text:Write a C++ program to implement the LCS algorithm covered in class for finding the Longest Common Subsequence (LCS) of two sequences. Provide comprehensive comments and explanations within your code to elucidate the logic and implementation of the dynamic programming approach. Note that LCS is different from a common substring. Test your program with the following two cases to verify the correctness of your implementation: Test Case 1: Given two sequences X and Y: X= (A, B, C, B, D, A, B) and Y = (B, D, C, A, B, A) Test Case 2: Given two gene sequences S1 and S2: S₁ = ACCGGTCGAGTGCGCGGAAGCCGGCCGAA S₂ = GTCGTTCGGAATGCCGTTGCTCTGTAAA
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