Write a C program to Find disjoint sets in a graph using disjoint set ADT operations FIND, UNION

Computer Networking: A Top-Down Approach (7th Edition)
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ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
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Write a C program to Find disjoint sets in a graph using disjoint set ADT operations FIND, UNION

Let us first discuss what disjoint sets in a graph is? Disjoint sets in a graph mean components of a graph. Each connected component is treated as a disjoint set since it has no relation with the other components. Each connection (edge) is said to be the relation between two nodes. Two nodes having a relation falls in the same set.


The algorithm is:
For each edge in the edge list:
If the nodes on the edge are in same set, do nothing, otherwise, we will UNION them as they have relations between them and should come under same set.
To check whether the two nodes are in same set we use FIND

 

NOTE: IN C PROGRAM ONLY PLEASE

 

Output: (attached picture)

Enter number of edges
6
Enter number of nodes
8
info for edge 1
Enter source node u: 1
Enter destination node v: 2
info for edge 2
Enter source node u: 1
Enter destination node v: 3
info for edge 3
Enter source node u: 2
Enter destination node v: 4
info for edge 4
Enter source node u: 2
Enter destination node v: 5
info for edge 5
Enter source node u: 6
Enter destination node v: 7
info for edge 6
Enter source node u: 7
Enter destination node v: 8
Numebr of disjoint set is :2
printing the parent array now:
1 1 1 1 1 6 6 6
Transcribed Image Text:Enter number of edges 6 Enter number of nodes 8 info for edge 1 Enter source node u: 1 Enter destination node v: 2 info for edge 2 Enter source node u: 1 Enter destination node v: 3 info for edge 3 Enter source node u: 2 Enter destination node v: 4 info for edge 4 Enter source node u: 2 Enter destination node v: 5 info for edge 5 Enter source node u: 6 Enter destination node v: 7 info for edge 6 Enter source node u: 7 Enter destination node v: 8 Numebr of disjoint set is :2 printing the parent array now: 1 1 1 1 1 6 6 6
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