Write a C++ program that will load 100 integers into array x. Separate the even from the odd valued elements. The procedure should place the even values in ascending order starting from the first location of the original array and place the odd values in ascending order starting from the last position of the origin array. Can u please continue this code. I really need help about this. //header files#include <iostream>using namespace std;int main(){ int x[100],evenX[100],oddX[100],even=0,odd=0,i,temp,j ; cout<<"Enter the 100 values for integer array :"; //prompt the user for(i=0;i<100;i++) { cin>>x[i]; //input from the user } for(int i=0;i<100;i++) if(x[i]%2==0) //chech whether value is even or odd { evenX[even]=x[i]; //if value is even,store the value in array even++; } else { oddX[odd]=x[i]; //if value is odd,store the value in array odd++; } //sort the even elements of the array for(i=0;i<=even;i++) { for(j=i+1;j<even;j++) { if(evenX[i]>evenX[j]) { temp =evenX[i]; evenX[i]=evenX[j]; evenX[j]=temp;
Write a C++ program that will load 100 integers into array x. Separate the even from the odd valued elements. The procedure should place the even values in ascending order starting from the first location of the original array and place the odd values in ascending order starting from the last position of the origin array.
Can u please continue this code. I really need help about this.
//header files
#include <iostream>
using namespace std;
int main()
{
int x[100],evenX[100],oddX[100],even=0,odd=0,i,temp,j ;
cout<<"Enter the 100 values for integer array :"; //prompt the user
for(i=0;i<100;i++)
{
cin>>x[i]; //input from the user
}
for(int i=0;i<100;i++)
if(x[i]%2==0) //chech whether value is even or odd
{
evenX[even]=x[i]; //if value is even,store the value in array
even++;
}
else
{
oddX[odd]=x[i]; //if value is odd,store the value in array
odd++;
}
//sort the even elements of the array
for(i=0;i<=even;i++)
{
for(j=i+1;j<even;j++)
{
if(evenX[i]>evenX[j])
{
temp =evenX[i];
evenX[i]=evenX[j];
evenX[j]=temp;
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