I know that the answer to this is C (Yes, because the product of three times 9.15 is greater than 13.82), but I am confused as to where the x 3 comes from? Would we be justified in assuming that we have equal variances for the hypothesis test reported below? (Thistwo-sample t-test examines the mean number of alcoholic drinks consumed each week by whether or not therespondent smokes or uses tobacco products.)Two-sample t test with equal variancesGroupNoYescombineddiffObs17734211MeanHa: diffePr(Tt) = 0.00007.07344614.941188.341232-7.86773diff mean (No) - mean (Yes)Ho: diffeStd. Err..Std. Dev. (95% Conf. Intervall.6875901 9.147791 5.716464 8.4304292.369947 13.81905 10.11948 19.762879.755173-11.57054 -4.164923.7172541 10.418721.8782826.927291Ha: diff !=0Pr|TI|t|) = 0.0000t-4.1888degrees of freedom -Ha: diff > @Pr(Tt) 1.0000No, because the standard deviations are not the sameYes, because the product of three times .69 is less than 2.37Yes, because the product of three times 9.15 is greater than 13.82No, because the standard errors are not equal209M

We first assumed that the samples are coming from normal distribution where means and variances are…

Would we be justified in assuming that we have equal variances for the hypothesis test reported below? (This two-sample t-test examines the mean number of alcoholic drinks consumed each week by whether or not the respondent smokes or uses tobacco products.) Two-sample t test with equal variances Group No Yes combined Obs 177 34 211 Mean Ha: diff < @ Pr(Tt) = 0.0000 7.073446 .6875901 14.94118 2.369947 8.341232 diff diff mean (No) - mean(Yes) Ho: diffe -7.86773 Std. Err. Std. Dev. (95% Conf. Intervall 9.147791 5.716464 8.430429 13.81905 10.11948 19.76287 7172541 10.41872 1.878282 6.927291 Ha: diff != e Pr(IT] It) 0.0000 -11.57054 -4.164923 degrees of freedon 9.755173 t-4.1888 No, because the standard deviations are not the same Yes, because the product of three times .69 is less than 2.37 Yes, because the product of three times 9.15 is greater than 13.82 No, because the standard errors are not equal 209 Ha: diff Pr(Tt) 1.0000

Would we be justified in assuming that we have equal variances for the hypothesis test reported below? (This two-sample t-test examines the mean number of alcoholic drinks consumed each week by whether or not the respondent smokes or uses tobacco products.) Two-sample t test with equal variances Group No Yes combined Obs 177 34 211 Mean Ha: diff < @ Pr(Tt) = 0.0000 7.073446 .6875901 14.94118 2.369947 8.341232 diff diff mean (No) - mean(Yes) Ho: diffe -7.86773 Std. Err. Std. Dev. (95% Conf. Intervall 9.147791 5.716464 8.430429 13.81905 10.11948 19.76287 7172541 10.41872 1.878282 6.927291 Ha: diff != e Pr(IT] It) 0.0000 -11.57054 -4.164923 degrees of freedon 9.755173 t-4.1888 No, because the standard deviations are not the same Yes, because the product of three times .69 is less than 2.37 Yes, because the product of three times 9.15 is greater than 13.82 No, because the standard errors are not equal 209 Ha: diff Pr(Tt) 1.0000

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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