I need help finding out the time complexity Of the if conditions Provided that the input size is N. For the following code. And the run time overall of the method. ```java/* worst case: how many times are the if conditions executed for a given input size of n? */public static void q(int n) { if( n < 0 ) return; if( n == 0 ) return; for( int i=0; i

Solution: Time complexity The length of the input determines how long it takes an algorithm to…

Answered: /* worst case: how many times are the…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

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I need help finding out the time complexity Of the if conditions Provided that the input size is N. For the following code. And the run time overall of the method.

```java
/* worst case: how many times are the if conditions executed for a given input size of n? */
public static void q(int n) {
if( n < 0 ) return;
if( n == 0 ) return;
for( int i=0; i<n; i++ ) {
for( int j=0; j<n; j++ ) {
if( i==0 || i==n-1 || j==0 || j==n-1 ) {
System.out.print("*");
}
else {
System.out.print(" ");
}
}
System.out.println();
}
}
/* How would you describe the runtime of above code? */
```

This code snippet defines a Java method `q` which prints a border pattern of asterisks ("*") of size `n x n`. The method uses nested loops to iterate over the indices `i` and `j`. It prints an asterisk at the border of the square (`i==0`, `i==n-1`, `j==0`, `j==n-1`) and a space elsewhere.

1. **Control Flow and Execution:**
- **Input validation:** If the input `n` is less than or equal to zero, the function immediately returns.
- **Outer loop:** Iterates `n` times for variable `i`.
- **Inner loop:** Iterates `n` times for variable `j` within each iteration of `i`.
- **Condition checks:** The `if` statement checks whether the current position is on the border and prints the corresponding character.

2. **Runtime Complexity:**
- The code has a complexity of \( O(n^2) \) since it uses two nested loops, each iterating `n` times. Each cell in the `n x n` grid is visited once.
```

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