Working Backwards Parte Deux. a.First, identify which functional groups changed during the reaction. Did stereochemistry change too? b. Based on your answers to A and B, what kind of reaction occurred here, SN1 or SN2? c.Suggest reagents and solvent that could accomplish this reaction.

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Chapter1: Chemical Foundations
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Working Backwards Parte Deux.

a.First, identify which functional groups changed during the reaction. Did stereochemistry change too?

b. Based on your answers to A and B, what kind of reaction occurred here, SN1 or SN2?

c.Suggest reagents and solvent that could accomplish this reaction. 

This image depicts a chemical transformation involving two steroid-like molecules. 

**Left Molecule:**
- The structure features a steroid framework with a chlorine (Cl) atom attached, visible in the lower left segment of the molecule.
- Notably, there are methoxy (OMe) groups present on both the left and upper sides of the structure.
- A hydroxyl group (OH) is present at the top right, attached to an isopropyl group.

**Right Molecule:**
- Similar to the left molecule, this structure maintains the steroidal backbone.
- The chlorine (Cl) atom from the left molecule is absent and has been replaced with a nitrile group (–C≡N), indicating a substitution reaction.
- Methoxy (OMe) groups and the hydroxyl group (OH) remain in the same positions as in the left molecule.

The question mark with an arrow suggests an unknown or unspecified reaction or series of reactions leading from the initial compound on the left to the final product on the right. This type of diagram is common in organic chemistry to illustrate transformations without specifying reagents or conditions.
Transcribed Image Text:This image depicts a chemical transformation involving two steroid-like molecules. **Left Molecule:** - The structure features a steroid framework with a chlorine (Cl) atom attached, visible in the lower left segment of the molecule. - Notably, there are methoxy (OMe) groups present on both the left and upper sides of the structure. - A hydroxyl group (OH) is present at the top right, attached to an isopropyl group. **Right Molecule:** - Similar to the left molecule, this structure maintains the steroidal backbone. - The chlorine (Cl) atom from the left molecule is absent and has been replaced with a nitrile group (–C≡N), indicating a substitution reaction. - Methoxy (OMe) groups and the hydroxyl group (OH) remain in the same positions as in the left molecule. The question mark with an arrow suggests an unknown or unspecified reaction or series of reactions leading from the initial compound on the left to the final product on the right. This type of diagram is common in organic chemistry to illustrate transformations without specifying reagents or conditions.
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