With zero initial conditions, the unit-step response of a LTI system is y(t) = e-3t+12u(t – 4) + u(t - 4) where u(t) is the unit-step function. Find the transfer function of the system.

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With zero initial conditions, the unit-step response of a LTI system is
y(t) = e 3t+12u(t - 4) + u(t – 4)
where u(t) is the unit-step function. Find the transfer function of the system.
3. Consider the following feedback system:
y(t)
r(t)
1
K
s3 + s2 + 2s +1
(a) Find the entire range of K so that the closed-loop system (i.e., between r(t) and y(t)) is stable.
) R che step reference input r(t) is given to the system, will y(t) perfectly track the step reference r(t) with
zero steady-state error? Why or Why not? Justify your answer.
arshoot less than or equal to 10% of the input magnitude and (2) the 2% settling time of the step feope
is less than or equal to 1 second. What are the locations of the poles of such a systemn:
Transcribed Image Text:With zero initial conditions, the unit-step response of a LTI system is y(t) = e 3t+12u(t - 4) + u(t – 4) where u(t) is the unit-step function. Find the transfer function of the system. 3. Consider the following feedback system: y(t) r(t) 1 K s3 + s2 + 2s +1 (a) Find the entire range of K so that the closed-loop system (i.e., between r(t) and y(t)) is stable. ) R che step reference input r(t) is given to the system, will y(t) perfectly track the step reference r(t) with zero steady-state error? Why or Why not? Justify your answer. arshoot less than or equal to 10% of the input magnitude and (2) the 2% settling time of the step feope is less than or equal to 1 second. What are the locations of the poles of such a systemn:
Expert Solution
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Since,we can answer only one question at a time.so,Providing you the Solution of first question only.Please post the rest of the Question Again.

Given:-

y(t)=e-3t+12u(t-4)+u(t-4)

intial Condition zero.

Formula used:-

x(t-to)e-stoXs...........(1)esotx(t)X(s-so).............(2)

 
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