With the new mean and standard deviation, how many standard deviations away from the mean is the value of 18.5 ounces? Is the value above or below the mean?
Question 4- Already Answered- See Question 5
After some time has passed, all of the chickens lay full-sized eggs. (When chickens first start laying, many of their eggs are small.) So, the mean weight goes up to 24 ounces. At the same time, the variation decreases, so the standard deviation goes down to 2 ounces.
Mark off a normal distribution with the numbers for the mean and each deviation by labeling the values for A, B, C, D, E, F, and G in the table.
Value | |
A | |
B | |
C | |
D | |
E | |
F | |
G |
A normal distribution is a continuous probability distribution that makes a bell-shaped curve of the data. It creates a symmetric distribution with the mean,
According to
The data in the normal distribution would be:
μ±1σ=68%μ±2σ=95%μ±3σ=99.7%μ±1σ=68%μ±2σ=95%μ±3σ=99.7%
Answer 4.
In this study, the data of chickens' eggs size was normally distributed with a mean (μ=24 ouncesμ=24 ounces) and the standard deviation (σ=2 ouncesσ=2 ounces).
According to the Empirical, if the data is following the normal distribution, 99.7% of data seen following a normal distribution falls within three standard deviations of the mean. According to this criteria, one standard deviation away from the mean includes 68% of data, two standard deviations away from the mean includes 95% of data, and within three standard deviations from the mean includes 99.7% of data.
The data would be distributed in the following manner
μ±1σ=68%μ±2σ=95%μ±3σ=99.7%μ±1σ=68%μ±2σ=95%μ±3σ=99.7%
The table calculation would be:
A=μ−3σB=μ−2σC=μ−1σD=μ+0σE=μ+1σF=μ+2σG=μ+3σA=μ-3σB=μ-2σC=μ-1σD=μ+0σE=μ+1σF=μ+2σG=μ+3σ
The table shows the calculation and value of egg size in a normal distribution table:
Calculation | Value | |
A | =24−3×2=24-3×2 |
18 |
B | =24−2×2=24-2×2 | 20 |
C | =24−1×2=24-1×2 | 22 |
D | =24+0×2=24+0×2 | 24 |
E | =24+1×2=24+1×2 | 26 |
F | =24+2×2=24+2×2 | 28 |
G | =24+3×2=24+3×2 | 30 |
The table showed that data would be distributed in a
Question 5 is the one I need assistance with.
Question 5
With the new mean and standard deviation, how many standard deviations away from the mean is the value of 18.5 ounces? Is the value above or below the mean?
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