With the following lists: ist1 = [x + y for x in ['a', 'b', 'c'] for y in ['1', '2', '3']] ist2 = [[x + y for x in ['a', 'b', 'c']] for y in ['1', '2', '3']] which option is true? Select one: A. len(list1) > len(list2) B. 'a1' is an element (or subelement) for list1 whereas '1a' is for list2 OC. list1 and list2 will error because numbers and letters cannot be added. D. Both A and B are true.

With the following lists: ist1 = [x + y for x in ['a', 'b', 'c'] for y in ['1', '2', '3']] ist2 = [[x + y for x in ['a', 'b', 'c']] for y in ['1', '2', '3']] which option is true? Select one: A. len(list1) > len(list2) B. 'a1' is an element (or subelement) for list1 whereas '1a' is for list2 OC. list1 and list2 will error because numbers and letters cannot be added. D. Both A and B are true.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

The two-dimensional lists m1 and m2 are identical if they have the same contents. Write a function that returns True if m1 and m2 are identical, usingthe following header:def equals(m1, m2): Write a test program that prompts the user to enter two lists of integers and displays whether the two are identical.
in python Integer num_samples is read from input, representing the number of data samples to be read from input. List data_list contains the data samples read from the remaining input. For each element in data_list: If the element is greater than 25, output the element followed by ' at index ', the element's index in the list, and ' is flagged'. Otherwise, output the element followed by ' at index ', the element's index in the list, and ' is normal'.
Question 2 For each of the following, fill in the appropriate initial accumulator value: let rec tail_sum_list lst acc = match 1st with I (] -> acc i h::t -> tail_sum_list t (h+acc) Correct initial accumulator: 0 let rec tail_strdup n str acc - if n = 0 then acc else tail_strdup (n-1) str (str^acc) Correct initial accumulator: = match 1st with let rec floatmul lst acc I [] -> acc I h::t -> floatmul t (h *. acc) Correct initial accumulator:
What does the following error message normally mean? IndexError: list index out of range Select one: а. This error normally indicates that you have tried to access an element of a list that doesn't exist. O b. This error normally means that you have used the range() function incorrectly. С. This error normally means that you have used a list where you should have used a tuple. d. This error normally means that you used too many lines of code in your program.
The function should be written in python language. Write a function called "zero_triples" to return all triples in a list of integers that sum to zero. You can assume the list won't contain any duplicates, and a triple should not use the same number more than once. [In]: zero_triples([1, 2, 4]) [Out]: [] [In]: zero_triples([-3, 1, 4, 2]) [Out]: [[1, 2, -3]] [In]: zero_triples([-9, 1, -3, 2, 4, 5, -4, -1]) [Out]: [[-9, 4, 5], [1, -3, 2], [-3, 4, -1], [5, -4, -1]]
11111 2) Name: 2. The following procedure is intended to return the number of times the value val appears in the list myList. The procedure does not work as intended. Line 01: PROCEDURE countNumOccurences (myList, val) Line 02: { Line 03: FOR EACH item IN myList Line 04: } BL Line 05: count 0 Line 06: IF(item = val) %3D Line 07: Line 08: count count + 1 :60 Line 10: { { RETURN(count) Line 11: Line 12: } Which of the following changes can be made so that the procedure will work as intended? a. Moving the statement in line 5 so that it appears between lines 2 and 3 C. Changing line 6 to IF(item = count) b. Changing line 6 to IF(myList[item] = val) d. Moving the statement in line 11 so that it appears between lines 9 and 10
The function count_contains_og in python takes a list of strings and returns how many strings in the list contain 'og' / 'OG' / 'oG' / 'Og' (check for 'og', ignoring case). Hint: Use the sequence membership operator in to help you check for 'og' in the individual strings. Create a lower-cased version of the string (lower), then use the in operator. For example: Test Result str_list = ['cat', 'dog', 'FROG', 'monkey'] print(count_contains_og(str_list)) 2 strlist = ["X", "x"] print(count_contains_og(strlist)) 0 list_of_one_og = ["Doggie"] print(count_contains_og(list_of_one_og)) 1
HAPTER 5: Lists and Dictiona st membership > 51621 O WorkArea Instructions eadline: 03/ 11:59pm EDT Given that k contains an integer and that play_list has been defined to be a list, write a expression that evaluates to True if the value assigned to k is an element of play_list. Additional Notes: play_list and k should not be modified
Help make a C++ program that:1. Queries the user for the name of a file of text.2. Opens the file, and maintains two lists: one list for words beginning with the letter"D" or "d", and a second list for words beginning with any other letter. Each listmust maintain words in alphabetical order.3. Each node in the list must contain the word and the number of times that the word appears.4. Display (a screen at a time) each of the lists showing the alphabetized list of words and thenumber of times that each appears. Please have the main function as the first function in the program. Please make the least amount of functions as possible. Like for the file input have the file error thing in the same function. And please add comments throughout the code.
] ] get_nhbr In the cell below, you are to write a function called "get_nhbr(Ist, graph)" that takes in two inputs: a list of vertices and a graph. The function is to return a list that contains the neighborhood of the vertices in 'Ist' (remember that this means you are finding the union of the individual vertices' neighborhoods). + Code + Markdown After compiling the above cell, you should be able to compile the following cell and obtain the desired outputs. print (get_nhbr(["A", "D"], {"A" : ["B"], "B" : ["A", "D", "E"], "C" : ["E"], "D":["B"], "E":["B","C","F"], "F":["E"]}), get_nhbr(["B", "C", "F"], {"A" : ["B"], "B" : ["A", "D", "E"], "C" : ["E"], "D":["B"], "E":["B","C","F"], "F":["E"]})) This should return ["B"] ["A", "D", "E"] Python Python
Which of the following statements regarding linked lists and arrays is correct? Group of answer choices: a. A dynamically resizable array makes insertions at the beginning of an array very efficient. b. Using a doubly linked list is more efficient than an array when accessing the ith element of a structure. c. A dynamically resizable array is another name for a linked list. d. Any type of list tends to be better than an array when there are a set number of maximum items known beforehand. e. If many deletions at any place in the structure were common, a linked list implementation would likely be preferable to an array
In Python Use the Design Recipe to write a function has_duplicates, which consumes a list and returns True if the list has any duplicate entries, False otherwise. Your function should return False if the list is empty