Suppose x is a normally distributed random variable with μ = 12 and o=2. Find each of the following probabilities.a. P(x214) b. P(x≤9) c. P(12.56 ≤x≤ 17.32) d. P(7.16 ≤x≤ 14.9)Click here to view a table of areas under the standardized normal curve.a. P(x ≥ 14) = (Round to three decimal places as needed.)ample Get more help.Table of Normal Curve AreasZ .00wwwww BENER CREEP BEESE GEGEE 56045 AWNIO0zPrint4996049972Done60IX

given data normal distributionμ = 12σ = 2

Answered: with μ = 12 and d a. P(x214) b. P(x≤9)…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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b. Sketch a standard normal curve and shade the area under the curve that lies between - 3 and - 2.1. Choose the correct graph below. А. В. С. OD. - 2.1 2.1 O 2.1 3 O 2.1 3 The area that lies between - 3 and - 2.1 is 0.98 (Round to four decimal places as needed.) N
00 T R AWM Z. Use the standard normal table to find the z-score that corresponds to the given percentile. If the area is not in the table, use the entry closest to the area. If the area is halfway between two entries, use the z-score halfway between the corresponding z-scores. If convenient, use technology to find the z-score. P72 Cliak to viouno The z-score that corresponds to P72 is (Round to two decimal places as needed.) Enter your answer in the answer box. ?. ll Jeffrey Jones 61 Lea V Stop Video Participants Chat Share Screen Record Reactions Unmute Type here to search 近。 PrtScn Home (口 F1 F2 F3 F4 F5 23 2$ 5. 9- 4. A. B.
K A company is developing a new high performance wax for cross country ski racing. In order to justify the price marketing wants, the wax needs to be very fast. Specifically, the mean time to finish their standard test course should be less than 55 seconds for a former Olympic champion. To test it, the champion will ski the course 8 times. The champion's times (selected at random) are 54.9, 63.7, 48.1, 53.9, 49.3, 47.4, 53.7, and 44.9 seconds to complete the test course. Should they market the wax? Assume the assumptions and conditions for appropriate hypothesis testing are met for the sample. Use 0.05 as the P-value cutoff level. Choose the correct null and alternative hypotheses below. Ο A. Ho:μ = 55 HAH55 Calculate the test statistic. ... t= OB. Ho:μ>55 HA:μ = 55 OD. Ho:μ<55 HAH=55 (Round to three decimal places as needed.) Calculate the P-value. P-value= (Round to four decimal places as needed.) Choose the correct clusion below. A. No, do not market the wax as there is insufficient…
Use the standard normal table to find the z-score that corresponds to the cumulative area 0.0072. If the area is not in the table, use the entry closest to the area. If the area is halfway between two entries, use the z-score halfway between the corresponding z-scores. Click to view page 1 of the standard normal table. LOADING... Click to view page 2 of the standard normal table. LOADING... z=enter your response here (Type an integer or decimal rounded to three decimal places as needed.)
Just need part d.
Sketch a standard normal curve and shade the area that lies to the left of a. -1.15 , b. 0.6 , c. 0 , and d. 4.2 . Then determine the area under the standard normal curve that lies in the area of interest for each part. The area to the left of -1.15 is (Round to four decimal places as needed.) The area to the left of 0.6 is (Round to four decimal places as needed.) The area to the left of 0 is (Round to four decimal places as needed.) The area to the left of 4.2 is (Round to four decimal places as needed.)
Find the proportion of the area given the following notations. Sketch a normal curve. Then shade the required region of the given probabilities1. P (z > 1.72)2. P (-1.08 < z < 2)
3) During a study, the weights of test subjects was recorded. The results are displayed in the graph below. Use the graph to determine the value of the following descriptive statistics Histogram of Wt (n=40) 20 15 10 10 100 150 X Values D How many weights were recorded? D) What is the average weight? O Approximate the standard deviation. d) What is the one-standard deviation interval around the mean? How many weights were within this interval? I What percentage of weights were within this interval? What is the two standard deviation interval around the mean? hi How many weights werE within this interval? What percentage of we were within thisterva What is the three standard deviation ntervalarund the mean K) How many weights were within this interv What percentage of weights were withiin thikinterval? 梦 $ hp
Draw the normal curve, shade the given area, then find Z-score. ANSWERS SHOULD BE IN 2 DECIMAL PLACES ONLY. a. If the area to the right of +Z is 0.0329 b. If the area to the left of -Z is 0.4522 c. If the area to the left of +Z is 0.9925
b. Sketch a standard normal curve and shade the area under the curve that lies to the right of 0.6. Choose the correct graph below. O A В. Oc. O D. 0 0.6 0 0.6 5 0.6 -0.6 0 The area to the right of 0.6 is (Round to four decimal places as needed.)

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with μ = 12 and d a. P(x214) b. P(x≤9) c. P(12.56 ≤x≤ 17.32) d. P(7.16 ≤x≤ 14.9) Click here to view a table of areas under the standardized normal curve. a. P(x2 14)=(Round to three decimal places as needed.) Table of Normal Curve Areas 123456789232 I x