With f(x) = 2x, f'(x) = 2, g(x) = 3x² - 1, and g'(x) = 6x, we are now ready to substitute these terms into the product rule to find dy for y = 2x(3x² - 1). Once the substitutions are made, dx continue to simplify. [f(x)g(x)] = f'(x)g(x) + f(x)g'(x) [2x(3x² − 1)] = 2(3x² − 1) + 2x(

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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dy
-
With f(x) = 2x, f'(x) = 2, g(x) = 3x² − 1, and g'(x) = 6x, we are now ready to substitute these terms into the product rule to find · for y = 2x(3x² − 1). Once the substitutions are made,
dx
continue to simplify.
d
dx
[f(x)g(x)] = f'(x)g(x) + f(x)g'(x)
-[2x(3x² − 1)] = 2(3x² − 1) + 2x
dx
=
=
6x².
To conclude, if y = 2x(3ײ – 1), then
- 2 +
dy
dx
=
- 2
X
Transcribed Image Text:dy - With f(x) = 2x, f'(x) = 2, g(x) = 3x² − 1, and g'(x) = 6x, we are now ready to substitute these terms into the product rule to find · for y = 2x(3x² − 1). Once the substitutions are made, dx continue to simplify. d dx [f(x)g(x)] = f'(x)g(x) + f(x)g'(x) -[2x(3x² − 1)] = 2(3x² − 1) + 2x dx = = 6x². To conclude, if y = 2x(3ײ – 1), then - 2 + dy dx = - 2 X
Expert Solution
Step 1

Given information:

fx=2xf'x=2gx=3x2-1g'x=6x

y=2x3x2-1

 

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