With a particular catalyst and at a given temperature, the oxidation of naphthalene to phthalic anhydride proceeds as follows: A = naphthalene = naphthaquinone S= phthalic anhydride T= oxidation products k = 0.21 s-1 k2 = 0.20 s-1 k3 = 4.2 s-1 k4 = 0.004 s-1
With a particular catalyst and at a given temperature, the oxidation of naphthalene to phthalic anhydride proceeds as follows: A = naphthalene = naphthaquinone S= phthalic anhydride T= oxidation products k = 0.21 s-1 k2 = 0.20 s-1 k3 = 4.2 s-1 k4 = 0.004 s-1
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
Related questions
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please answer the question. avoid typing your answers

Transcribed Image Text:With a particular catalyst and at a given temperature, the oxidation of
naphthalene to phthalic anhydride proceeds as follows:
A = naphthalene
R = naphthaquinone
S = phthalic anhydride
k = 0.21 s-1
kz = 0.20 s-1
k3 = 4.2 s-1
k4 = 0.004 s-1
R3
T= oxidation products
What reactor type gives the maximum yield of phthanc anhydride? Roughly
estimate this yield and the fractional conversion of naphthalene which will
give this yield. Note the word “roughly".
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Follow-up Questions
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Follow-up Question
why is k13 + k2 added as series but not as inverse since they are in parallel
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why is reaction k1 and k3 treated as parallel?
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