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Will you please answer the following that can be seen in the images?

Will you please answer the following that can be seen in the images?

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Will you please answer the following that can be seen in the images?

An electric charge Q is distributed uniformly along a thick and enormously long conducting wire with radius R and length L. Using Gauss's law, what is the electric field at distance r perpendicular to the wire? (Consider the cases inside and outside the wire) Solution To find the electric field inside at r distance from the wire we will use the Gauss's law which is expressed as We will choose a symmetric Gaussian surface, which is the surface a cylinder excluding its ends, then evaluate the dot product to obtain (Eguation t) Case 1: Inside the wire Since, r falls inside the wire, then all the enclosed charge must be: On the other hand, the Gaussian surface inside the wire is given by Using Equation 1, the electric field in simplified form is
Transcribed Image Text:An electric charge Q is distributed uniformly along a thick and enormously long conducting wire with radius R and length L. Using Gauss's law, what is the electric field at distance r perpendicular to the wire? (Consider the cases inside and outside the wire) Solution To find the electric field inside at r distance from the wire we will use the Gauss's law which is expressed as We will choose a symmetric Gaussian surface, which is the surface a cylinder excluding its ends, then evaluate the dot product to obtain (Eguation t) Case 1: Inside the wire Since, r falls inside the wire, then all the enclosed charge must be: On the other hand, the Gaussian surface inside the wire is given by Using Equation 1, the electric field in simplified form is
Case 2: Outside the wire Since, r falls outside the wire, then, all the charge must be enclosed, thus qenc On the other hand, the Gaussian surface outside the wire is given by Using Equation 1, the electric field in simplified form is
Transcribed Image Text:Case 2: Outside the wire Since, r falls outside the wire, then, all the charge must be enclosed, thus qenc On the other hand, the Gaussian surface outside the wire is given by Using Equation 1, the electric field in simplified form is
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