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Will dew (liquid water) form at 25°C if PH.O is 3210 Pa? Provide a brief explanation justifying your answer. (Note that there is data for water on the updated equation sheet.)

Will dew (liquid water) form at 25°C if PH.O is 3210 Pa? Provide a brief explanation justifying your answer. (Note that there is data for water on the updated equation sheet.)

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Will dew (liquid water) form at 25°C if PH.O is 3210 Pa? Provide a brief explanation justifying your answer. (Note that there is data for water on the updated equation sheet.)
Transcribed Image Text:Will dew (liquid water) form at 25°C if PH.O is 3210 Pa? Provide a brief explanation justifying your answer. (Note that there is data for water on the updated equation sheet.)
Data for H2O AH° = 40.65 kJ mol AH° 46.66 kJ/mol AH = 6.010 kJ mol' M= 18.02 g mol"' %3D %3D vap sub fus C„„(8)=33.6 J K' mol" Tiriple point = 273.16 K K, = 0.51 K kg mol| C„„(s)= 36.2 J K' mol" C„(!)=75.3 J K' mol" P,m Tjus = 273.15 K PH.o = 3173 Pa at 298 K density of liquid water = 0.9999 g mL' Tyap = 373.15 K Pıriple point = 611 Pa density of ice = 0.915 g mL'' K, =1.86 K kg mol"
Transcribed Image Text:Data for H2O AH° = 40.65 kJ mol AH° 46.66 kJ/mol AH = 6.010 kJ mol' M= 18.02 g mol"' %3D %3D vap sub fus C„„(8)=33.6 J K' mol" Tiriple point = 273.16 K K, = 0.51 K kg mol| C„„(s)= 36.2 J K' mol" C„(!)=75.3 J K' mol" P,m Tjus = 273.15 K PH.o = 3173 Pa at 298 K density of liquid water = 0.9999 g mL' Tyap = 373.15 K Pıriple point = 611 Pa density of ice = 0.915 g mL'' K, =1.86 K kg mol"
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